I'm not sure how to write the rule, but every time you add one more to the sum of the last two. First, you add 1, then 2, then 3. 1+1=2 2+2=4 4+3=7 7+4=11 and so on. I hope this helps!
Answer:
y = 4 or y = 6
Step-by-step explanation:
2log4y - log4 (5y - 12) = 1/2
2log_4(y) - log_4(5y-12) = log_4(2) apply law of logarithms
log_4(y^2) + log_4(1/(5y-12)) = log_4(/2) apply law of logarithms
log_4(y^2/(5y-12)) = log_4(2) remove logarithm
y^2/(5y-12) = 2 cross multiply
y^2 = 10y-24 rearrange and factor
y^2 - 10y + 24 = 0
(y-4)(y-6) = 0
y= 4 or y=6
Short Answer D
P(1) = 1(1+1)(2*1 + 1)/6
P(1) = 1(2)(2 +1) / 6
P(1) = 1(2)(3)/6
P(1) = 1
P(2) = 2(2+1)(2*2 + 1) / 6
P(2) = 2(3)(5) / 6
P(2) = 5 So this formula is adding as it goes along. To Find the Total all we need do is use the formula to calculate P(1) to P(7)
P(7) = 7*(7 + 1)(2*7 + 1)/6
P(7) = 7 * 8 * 15 / 6
P(7) = 7 * 4 * 5
P(7) = 140 <<<< Answer
Answer:
<h2>x= -3</h2>
Step-by-step explanation:
Answer:
900 divided by 30.48 =
Step-by-step explanation:
<u> 0 0. 0 3 3</u>
9 0 0 3 0. 4 8 0
− 0
3 0
<u> − 0 </u>
3 0 4
<u> − 0 </u>
3 0 4 8
<u> − 2 7 0 0 </u>
3 4 8 0
− <u>2 7 0 0</u>
7 8 0
Your answer is now many
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