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pshichka [43]
3 years ago
10

Find the unknown angle

Mathematics
2 answers:
arlik [135]3 years ago
8 0
Acute is the unknown angle
topjm [15]3 years ago
7 0
525267227727272727272727
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(X^4)-(45x^2)+324 what are the zeroes? And how many turning points?
dmitriy555 [2]

Zeroes:

We must solve

x^4-45x^2+324=0

To do so, we define the auxiliary variable t=x^2. The equation becomes

t^2-45t+324=0

The quadratic formula yields the solutions

t=9,\quad t=36

Substituting back t=x^2 gives

x^2=9 \iff x=\pm 3,\quad x^2=36 \iff x=\pm 6

So, the zeroes are -6, -3, 3, 6.

Turning points:

Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.

We have

f(x)=x^4-45x^2+324 \implies f'(x)=4x^3-90x

If we set the derivative to be zero, we have

4x^3-90x=0 \iff x(4x^2-90)=0

So, the derivative is zero if x=0 or

4x^2=90 \iff 2x^2=45 \iff x^2=\dfrac{45}{2}\iff x=\pm\sqrt{\dfrac{45}{2}}

6 0
3 years ago
You go for a run on monday you run 2.41Km on tuesday you ran the same distance how far did you ran altogether
FrozenT [24]

Answer: 4.82 km

Step-by-step explanation:

You went for a run on Monday.

You then went on a run on Tuesday as well. On this day you ran 2.41 km and it is said that you ran the same distance on both days which means you ran for 2.41 km on Monday as well.

The total distance you ran is therefore:

= 2.41 + 2.41

= 4.82 km

4 0
3 years ago
Calling the math genusis over here !! I need this question answered plz .
Ivahew [28]
Y-intercept is (0,4)

Hope this helped!
8 0
3 years ago
Read 2 more answers
A cooler measures 30 cm wide, 30 cm long, and 25 cm tall. Which is the correct unit of measurement to use when describing the am
Maurinko [17]
Since we are using 3 sides of measurement and are looking for a volume, or a 3rd dimensional amount, the correct unit of measure is going to cm3, which is B.).
I hope this helps!
8 0
3 years ago
Make a table with the domain of {2,3,4,5,6} and draw a graph of the absolute value function y = 2|x-4| + 3.
Jet001 [13]

Answer:

<h2>In the attachment.</h2>

Step-by-step explanation:

|a|=\left\{\begin{array}{ccc}a&for\ a\geq0\\-a&for\ a

Put each value of x from the set {2, 3, 4, 5, 6}

to the equation y = 2|x - 4| + 3:

x = 2 → y = 2|2 - 4| + 3 = 2|-2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (2, 7)

x = 3 → y = 2|3 - 4| + 3 = 2|-1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (3, 5)

x = 4 → y = 2|4 - 4| + 3 = 2|0| + 3 = 2(0) + 3 = 0 + 3 = 3 → (4, 3)

x = 5 → y = 2|5 - 4| + 3 = 2|1| + 3 = 2(1) + 3 = 2 + 3 = 5 → (5, 5)

x = 6 → y = 2|6 - 4| + 3 = 2|2| + 3 = 2(2) + 3 = 4 + 3 = 7 → (6, 7)

Mark the points in the coordinates system.

The domain is only five numbers, therefore the graph of this function is only five points.

5 0
3 years ago
Read 2 more answers
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