(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Use a system of equations
C+P=1132
3P=C
Substitute C in first equation as
3P+P=1132
Simplify
4P=1132
Solve
P=1132/4
P=283
NOW SOLVE FOR C SUBSTITUTING P VALUE IN FIRST EQUATION
C+283=1132
C=1132-283
C=849
Printer = 283$
Computer = 849$
Answer:19.3
Step-by-step explanation:
96+28=124
6x+8=124
124-8=116
6x=116
116/6
x=19.3
The answer is B.
The attached file is how I got the answer.
Hope this helped :)
4
5x - 4 = 16
Add four to both sides
5x = 20
Divide both sides by 5
x = 4
