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3 years ago

You have a standard deck of cards. The deck has 52 total cards and contains 4 suits: hearts, clubs, diamonds, and

Mathematics

2 answers:

umka21 [38]3 years ago

7 0

Answer:

P(A)=0.25

P(B)=0.077

P(AB)=0.192

P(BA)=0.083

Check below for the full numbers, I rounded it for you.

Step-by-step explanation:

What is P(A), the probability that the card is a club?

So whenever you get a deck of cards you'll have 52 which have 4 suits, think of it like UNO, and club is one of the suit's name! This mean all this question is asking you is the probability of getting a club out of the 52 cards which is

52/4=13

So we know that there is 13 club cards.

Meaning the probability is a 25% since you can only get it 1/4 of the time.

P(A)=0.25

What is P(B), the probability that the card is a 5?

Same as what I stated earlier but this time you only have 4 cards that can be a "5" out of the 52 cards.

4/52=0.076923

P(B)=0.077

What is P(A and B), the probability that the card is a club and a 5?

Keep a eye on the working "and" this means it's referring to the possibility of getting a club and a 5 and since this can only happen once the chances are extremely slim.

1/52=0.1923076

P(AB)=0.192

What is P(BA), the conditional probability that the card is a 5 given that it is a club?

This assumes that you're only drawing from a deck of ONLY clubs so the chances of getting a 5 in that stack.

1/12=0.08333 (3 keeps going)

P(BA)=0.083

(This one might be wrong since I haven't done conditional probability in a long time but I feel somewhat confident, I do feel confident about the rest so no worries.)

Is P(BA) = P(B)? Are the events A and B independent?

No, P(BA) = P(B) is not true since A and B do influence one another since what if I get a 5 without replacement this results in change of chances of A.

Amiraneli [1.4K]3 years ago

7 0

Answer:

1.1/4

2.1/13

3.1/52

4.1/13

5. Yes p(B/A)=P(B) and Yes, events A and B are independent events.

Step-by-step explanation:

khan academy walk through

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$\huge\boxed{\text{D)} \ 15x^4 + 2x^3 - 8x^2 - 22x - 15}$

Step-by-step explanation:

We can solve this multiplication of polynomials by understanding how to multiply these large terms.

To multiply two polynomials together, we must multiply each term by each term in the other polynomial. Each term should be multiplied by another one until it's multiplied by all of the terms in the other expression.

We can do this by focusing on one term in the first polynomial and multiplying it by all the terms in the second polynomial. We'd then repeat this for the remaining terms in the second polynomial.

Let's first start by multiplying the first term of the first polynomial, $3x^2$ , by all of the terms in the second polynomial. ( $5x^2+4x+5$ )

$3x^2 \cdot 5x^2 = 15x^4$
$3x^2 \cdot 4x = 12x^3$
$3x^2 \cdot 5 = 15x^2$

Now, we can add up all these expressions to get the first part of our polynomial. Ordering by exponent, our expression is now

$\displaystyle 15x^4 + 12x^3 + 15x^2$

Now let's do the same with the second term ( $-2x$ ) and the third term ( $-3$ ).

$-2x \cdot 5x^2 = -10x^3$
$-2x \cdot 4x = -8x^2$
$-2x \cdot 5 = -10x$

Adding on to our original expression: $\displaystyle 15x^4 + 12x^3 - 10x^3 + 15x^2 - 8x^2 - 10x$

$-3 \cdot 5x^2 = -15x^2$
$-3 \cdot 4x = -12x$
$-3 \cdot 5 = -15$

Adding on to our original expression: $\displaystyle 15x^4 + 12x^3 - 10x^3 + 15x^2 - 8x^2 - 15x^2 - 10x - 12x - 15$

Phew, that's one big polynomial! We can simplify it by combining like terms. We can combine terms that share the same exponent and combine them via their coefficients.