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PilotLPTM [1.2K]
3 years ago
14

HELP TIMER Write the equation of a hyperbola centered at the origin with x-intercept +/- 4 and foci of +/-2(squareroot 5)

Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

Answer:

\frac{x2}{a} - \frac{y2}{b2} = 1

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

\frac{X2}{16} - \frac{b}{4} = 1

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that  a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

I don't feel like explaining so...

a. = 4

The foci c is at +/-2√5, using c² = a² + b²:

B = 2

Substituting the value of a and b to get the equation of the hyperbola:

\frac{x2}{a2} -      \frac{y2}{b2} = 1  

\frac{x2}{16} - \frac{b2}{4} = 1

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