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PilotLPTM [1.2K]
3 years ago
14

HELP TIMER Write the equation of a hyperbola centered at the origin with x-intercept +/- 4 and foci of +/-2(squareroot 5)

Mathematics
1 answer:
nikitadnepr [17]3 years ago
4 0

Answer:

\frac{x2}{a} - \frac{y2}{b2} = 1

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

\frac{X2}{16} - \frac{b}{4} = 1

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that  a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

I don't feel like explaining so...

a. = 4

The foci c is at +/-2√5, using c² = a² + b²:

B = 2

Substituting the value of a and b to get the equation of the hyperbola:

\frac{x2}{a2} -      \frac{y2}{b2} = 1  

\frac{x2}{16} - \frac{b2}{4} = 1

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The first four terms of the sequence are 3 , 6 , 12 , 24

Step-by-step explanation:

We need to find the first four terms of the sequence a_{n}=2a_{n-1}

where a_{1}=3 to find them do that

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∵ a_{n}=2a_{n-1}

- Substitute n by 2 to find the 2nd term

∴ a_{2}=2a_{2-1}

∴ a_{2}=2a_{1}

∵ a_{1}=3

∴ a_{2}=2(3)

∴ a_{2}=6

- Substitute n by 3 to find the 3rd term

∴ a_{3}=2a_{3-1}

∴ a_{3}=2a_{2}

∵ a_{2}=6

∴ a_{3}=2(6)

∴ a_{3}=12

- Substitute n by 4 to find the 4th term

∴ a_{4}=2a_{4-1}

∴ a_{4}=2a_{3}

∵ a_{3}=12

∴ a_{4}=2(12)

∴ a_{4}=24

The first four terms of the sequence are 3 , 6 , 12 , 24

Learn more:

You can learn more about the sequences in brainly.com/question/1522572

#LearnwithBrainly

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