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Yanka [14]
3 years ago
10

Karim's dog weighs 1.5 pounds less than double the weight of Frank's dog. Karim's dog weighs 15 pounds. Which equation and solut

ion can be used to find w, the weight of Frank's dog?
Group of answer choices

15 = 2w + 1.5; w= 6.75

15 = 2w - 1.5; w = 8.25

w - 15 = 1.5; w = -13.5

w + 15 = 1.5; w= 16.5
Mathematics
1 answer:
ANEK [815]3 years ago
8 0

Answer:

Step-by-step explanation:

Karim's dog = 15 pounds

Frank dog = 2x more pounds than Karim's dog + 1.5 pounds

(Karim) Equation 1: 15 = Frank

(Frank) Equation 2: 2w + 1.5

joining equation 1 and 2

15 = 2w + 1.5

Solve

15 - 1.5 = 2w

13.5 = 2w ÷ 2

w = 6.75

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A rectangular prism with a avolume of 6 cubic units is filled with cubes with side lengths of 1/2 unit. How many 1/2 units does
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Answer:

48 cubes

Step-by-step explanation:

<u><em>The complete question is</em></u>

A rectangular prism with a volume of 6 cubic units is filled with cubes with side lengths of 1/2 unit. How many 1/2 unit cubes does it take to fill the prism?

step 1

Find the volume of the cube

The volume of the cube is equal to

V=b^{3}

where

b is the length side of the cube

we have

b=\frac{1}{2}\ units

substitute

V=(\frac{1}{2})^{3}

V=\frac{1}{8}\ units^{3}

step 2

To find out how many half-unit cubes are needed to fill the prism, divide the volume of the prism by the volume of the cube

6:\frac{1}{8}=48\ cubes

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What precent of change would 56 decreased to 14 be?
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Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist
Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths  = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

\frac{70}{100}\times 60=42

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

\frac{75}{100}\times 42=31.5

Number of students who need help in computer science and enrolled in his class after school hours

\frac{30}{100}\times 60=18

Therefore, there are 31.5+18=49.5 students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

\frac{49.5}{60}\times 100=82.5\%

Hence, there are 82.5% after school students who are enrolled in his classes.


6 0
4 years ago
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