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3 years ago

73=( 3)/(43) Need to find the missing number before the 3

Mathematics

1 answer:

Butoxors [25]3 years ago

3 0

Answer:

the missing number is 84

Step-by-step explanation:

Let the missing number be represented by N. Then we have ...

7*3 = N*3/(4*3)

Canceling common factors on the right, we have ...

7*3 = N/4

Multiplying by 4 gives ...

4*7*3 = N = 84

The missing number is 84.

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Solve the system of equations. −5y−10x=45 −3y+10x=−5

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3 years ago

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EastWind [94]

Answer:

Step-by-step explanation:

1. First, let's take any two points from the graph. For this case, I'm going to take (3,0) and (0,-3).

2. To find the slope given two points, we have to apply the formula $\frac{y_2-y_1}{x_2-x_1}$ and plug in the corresponding values:

$\frac{-3-0}{0-3}$
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2 years ago

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2 years ago

Seventy percent of light aircraft that disappear while in flight in a certain country are subsequently discovered. Of the aircra

alukav5142 [94]

Answer:

Figure out the various probabilities first, that will make the rest of the questions easier:

P(discovered) = .7

P(not discovered) = 1 - .7 = .3

P(locator|discovered) = .6

P(no locator|discovered) = 1 - .6 = .4

P(locator|not discovered) = 1 - .9 = .1

P(no locator|not discovered) = .9

P(discovered and locator) = .7 * .6 = .42

P(discovered and no locator) = .7 * .4 = .28

P(not discovered and locator) = .3 * .1 = .03

P(not discovered and no locator) = .3 * .9 = .27

a) The total probability that an aircraft has a locator is .42 + .03 = .45. So the probability it will not be discovered, given it has a locator, is .03/.45 = .067

b) The total probability that an aircraft does not have a locator is .28 + .27 = .55. So the probability it will be discovered, given it does not have a locator, is .28/.55 = .509

c) Probability that 7 are discovered = C(10,7) * P(discovered|locator)^7 * P(not discovered|locator)^3

We already figured out P(not discovered|locator) = .067, so P(discovered|locator) = 1-.067 = .933. C(10,7) = 10*9*8, so we can compute total probability: 10*9*8 * .933^7 * .067^3 = .133

Step-by-step explanation:

3 0

3 years ago

7*3=( *3)/(4*3) Need to find the missing number before the *3

73=( 3)/(43) Need to find the missing number before the 3