4 years ago

73=( 3)/(43) Need to find the missing number before the 3

Mathematics

1 answer:

Butoxors [25]4 years ago

3 0

Answer:

the missing number is 84

Step-by-step explanation:

Let the missing number be represented by N. Then we have ...

7*3 = N*3/(4*3)

Canceling common factors on the right, we have ...

7*3 = N/4

Multiplying by 4 gives ...

4*7*3 = N = 84

The missing number is 84.

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7*3=( *3)/(4*3) Need to find the missing number before the *3

73=( 3)/(43) Need to find the missing number before the 3