Question

Write an equation in slope intercept form that is perpendicular to 3x + 2y equals 12 and passes through the point (1,2)​

Answer 1

Answer:

The equation is y = (2/3)x + (4/3).

Step-by-step explanation:

First, you have to change the equation into slope-intecept formula to find its gradient (slope) :

$3x + 2y = 12$

$2y = - 3x + 12$

$y = - \frac{3}{2}x + 6$

Given that when a line is perpendicular to the other line, their slope value multiplied, will form -1. Next, we have to find the slope for line :

$m1 \times m2 = - 1$

$- \frac{3}{2} \times m2 = - 1$

$m2 = - 1 \div - \frac{3}{2}$

$m2 = \frac{2}{3}$

Lastly, we have to subatitute the x and y values into the equation, to find its intercept value :

$y = \frac{2}{3}x + b$

$let \: x = 1,y = 2$

$2 = \frac{2}{3} (1) + b$

$b = 2 - \frac{2}{3}$

$b = \frac{4}{3}$

$y = \frac{2}{3} x + \frac{4}{3}$