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jonny [76]
4 years ago
12

Heather, Ahmad, and Pablo sent a total of 76 text messages during the weekend. Pablo sent 2 times as many messages as Ahmad. Hea

ther sent 8 fewer messages than Ahmad. How many messages did they each send?
Mathematics
2 answers:
Ksivusya [100]4 years ago
8 0
Well, we know all three sent altogether 76 text messages
so... let us say, the amount of text for each is
Heather sent "h" amount
Ahmand sent "a" amount
and
Pablo sent "p" amount
so.. all three sent 76, meaning
h + a + p = 76
we know that, whatever "h" and "a" and "p" are

Pablo, send twice as much as Ahmad
so, if Ahmad sent "a", Pablo then sent 2 * a or 2a

Heather sent 8 less than Ahmad
so, if Ahmad sent "a", Heather then sent a - 8

thus \bf \begin{array}{llllll}
h&+&a&+&p&=76\\
\uparrow &&&&\uparrow \\
a-8&&&&2a
\end{array} \implies (a-8)+a+(2a)=76

solve for "a", to find how many Ahmad sent
Heather sent 8 less than that
and
Pablo sent, twice as much
FrozenT [24]4 years ago
7 0
Ahmad - 21 (x)
Pablo - 42 (2x)
Heather - 13 (x-8)

2x + x + x - 8 = 76
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$5000 dollars is borrowed for 3 months at an annual interest rate of 18%. How much interest must be paid?
PIT_PIT [208]

Answer:

Step-by-step explanation:

18:12*3=4,5

5000*4,5:100=225

5000+225=5225

7 0
3 years ago
(1.357 X 10^9) + 590,000 =
borishaifa [10]

Answer:

1.35759 x 10 ⁹

Step-by-step explanation:

i hope this helped

7 0
3 years ago
The length of a rectangle is 3 times the width. If the perimeter is to be greater than 56 meter. What are the lossible values fo
lidiya [134]

Answer:

w > 7

Step-by-step explanation:

L = 3w

2L + 2w > 56

sub for L

2(3w) + 2w > 56

6w + 2w > 56

8w > 56

w > 7


Check: L = 3(8)

L = 24

2(24) + 2(8) > 56

48 + 16 > 56

64 > 56

7 0
3 years ago
Read 2 more answers
The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep
Alchen [17]
Ooh, fun

geometric sequences can be represented as
a_n=a(r)^{n-1}
so the first 3 terms are
a_1=a
a_2=a(r)
a_2=a(r)^2

the sum is -7/10
\frac{-7}{10}=a+ar+ar^2
and their product is -1/125
\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3

from the 2nd equation we can take the cube root of both sides to get
\frac{-1}{5}=ar
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r
subsituting -1/5 for ar
\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r
which simplifies to
\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for ax^2+bx+c=0
x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}
so
for 2r²-5r+2=0
a=2
b=-5
c=2

r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}
r=\frac{5 \pm \sqrt{25-16}}{4}
r=\frac{5 \pm \sqrt{9}}{4}
r=\frac{5 \pm 3}{4}
so
r=\frac{5+3}{4}=\frac{8}{4}=2 or r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}

use them to solve for the value of a
\frac{-1}{5}=ar
\frac{-1}{5r}=a
try for r=2 and 1/2
a=\frac{-1}{10} or a=\frac{-2}{5}


test each
for a=-1/10 and r=2
a+ar+ar²=\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}
it works

for a=-2/5 and r=1/2
a+ar+ar²=\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}
it works


both have the same terms but one is simplified

the 3 numbers are \frac{-2}{5}, \frac{-1}{5}, and \frac{-1}{10}
6 0
4 years ago
For the function f(x) = 7/2x-16, what is the difference quotient for all nonzero values of h?
sergey [27]

Answer:

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}

Step-by-step explanation:

Given

f(x) = \frac{7}{2}x - 16

Required

The difference quotient for h

The difference quotient is calculated as:

\frac{f(x + h) - f(x)}{ h}

Calculate f(x + h)

f(x) = \frac{7}{2}x - 16

f(x+h) = \frac{7}{2}(x+h) - 16

f(x+h) = \frac{7}{2}x+ \frac{7}{2}h- 16

The numerator of \frac{f(x + h) - f(x)}{ h} is:

f(x + h) - f(x) =  \frac{7}{2}x+ \frac{7}{2}h- 16 -(\frac{7}{2}x - 16)

f(x + h) - f(x) =  \frac{7}{2}x+ \frac{7}{2}h- 16 -\frac{7}{2}x + 16

Collect like terms

f(x + h) - f(x) =  \frac{7}{2}x  -\frac{7}{2}x + \frac{7}{2}h- 16 + 16

f(x + h) - f(x) = \frac{7}{2}h

So, we have:

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h \div h

Rewrite as:

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}h * \frac{1}{h}

\frac{f(x + h) - f(x)}{ h} = \frac{7}{2}

5 0
3 years ago
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