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jonny [76]
3 years ago
12

Heather, Ahmad, and Pablo sent a total of 76 text messages during the weekend. Pablo sent 2 times as many messages as Ahmad. Hea

ther sent 8 fewer messages than Ahmad. How many messages did they each send?
Mathematics
2 answers:
Ksivusya [100]3 years ago
8 0
Well, we know all three sent altogether 76 text messages
so... let us say, the amount of text for each is
Heather sent "h" amount
Ahmand sent "a" amount
and
Pablo sent "p" amount
so.. all three sent 76, meaning
h + a + p = 76
we know that, whatever "h" and "a" and "p" are

Pablo, send twice as much as Ahmad
so, if Ahmad sent "a", Pablo then sent 2 * a or 2a

Heather sent 8 less than Ahmad
so, if Ahmad sent "a", Heather then sent a - 8

thus \bf \begin{array}{llllll}
h&+&a&+&p&=76\\
\uparrow &&&&\uparrow \\
a-8&&&&2a
\end{array} \implies (a-8)+a+(2a)=76

solve for "a", to find how many Ahmad sent
Heather sent 8 less than that
and
Pablo sent, twice as much
FrozenT [24]3 years ago
7 0
Ahmad - 21 (x)
Pablo - 42 (2x)
Heather - 13 (x-8)

2x + x + x - 8 = 76
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⇒    =\frac{\frac{16.06-16}{0.24} }{\sqrt{96} }

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⇒    =2.45

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i.e.,

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Rectangle poster is 3 times as long as wide perimeter is 24 in
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w= width

l = 3w

P = 2(l+w)

substitute

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3 0
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There is a parallelogram ABCD with diagonals AC and BD. The diagonals AC and BD intersects each other at point E. Side AB is con
grandymaker [24]

Answer:

SAS theorem

Step-by-step explanation:

Given

\square ABCD

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD

\angle BAC = \angle  DCA

Required

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From the question, we understand that:

AC and BD intersects at E.

This implies that:

\[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC

and

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED

So, the congruent sides and angles of △ABE and △CDE are:

\[ \lvert \[ \lvert AB =\[ \lvert \[ \lvert CD ---- S

\angle BAC = \angle  DCA ---- A

\[ \lvert \[ \lvert BE = \[ \lvert \[ \lvert ED or \[ \lvert \[ \lvert AE = \[ \lvert \[ \lvert EC  --- S

<em>Hence, the theorem that compares both triangles is the SAS theorem</em>

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