Given:
x lies in the III quadrant.
To find:
The values of .
Solution:
It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.
We know that,
x lies in the III quadrant. So,
Now,
And,
We know that,
Therefore, the required values are .
Answer:
it is 1/8- 5/8 smallest to biggesst
4x + 10y
Hope it’s right
Best luck with your studying
Answer: -8 and 9
Explanation: -8 x 9 = -72 and -8 + 9 = 1
Answer:
D: 6 5/6
Step-by-step explanation:
Solve for a:
a + 7/6 = 8
Put each term in a + 7/6 over the common denominator 6: a + 7/6 = (6 a)/6 + 7/6:
(6 a)/6 + 7/6 = 8
(6 a)/6 + 7/6 = (6 a + 7)/6:
(6 a + 7)/6 = 8
Multiply both sides of (6 a + 7)/6 = 8 by 6:
(6 (6 a + 7))/6 = 6×8
(6 (6 a + 7))/6 = 6/6×(6 a + 7) = 6 a + 7:
6 a + 7 = 6×8
6×8 = 48:
6 a + 7 = 48
Subtract 7 from both sides:
6 a + (7 - 7) = 48 - 7
7 - 7 = 0:
6 a = 48 - 7
48 - 7 = 41:
6 a = 41
Divide both sides of 6 a = 41 by 6:
(6 a)/6 = 41/6
6/6 = 1:
Answer: a = 41/6 or a= 6 5/6