What makes apparent magnitude different from absolute brightness? Give an example in your response.
1 answer:
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Answer:
Step-by-step explanation:
Given
Shape: Rectangle
Diagonals: AC and BD
Required
Determine BD
From the question, we understand that the shape is a rectangle and its diagonals are AC and BD
Every rectangle has 2 diagonals, both of which are equal.
This implies that:
Recall that:
Hence,
Answer:
(12,0) and (3, -1) and (0,-4/3)
Step-by-step explanation:
To find if a point makes an equation true, just substitute its x and y values in in the equation and simplify.
1) Let's test the point (12,0). Substitute 12 for x and 0 for y in the equation:
12 does equal 12, so (12,0) makes the equation true.
2) Let's test the point (0, 12). Substitute 0 for x and 12 for y in the equation:
However, -108 does not equal 12, so (0,12) does not make the equation true.
3) Let's test the point (3, -1). Substitute 3 for x and -1 for y in the equation:
12 does equal 12, so (3, -1) makes the equation true.
4) Let's test the point (0, -4/3). Substitute 0 for x and -4/3 for y in the equation:
12 does equal 12, so (0, -4/3) makes the equation true.