Answer:
The answer would be 26%
Step-by-step explanation:
Answer:
-5 degrees
Step-by-step explanation:
In this scenario, since the final temperature was the temperature that existed at midnight then that value is subtracted from the initial temperature which was at 6:00 PM. Therefore we do the following calculation...
(-2) - 3 = x
-5 = x
Finally, we can see that there was a change in temperature of -5 degrees between 6:00 P.M. and Midnight. Meaning that the temperature during this time dropped a total of 5 degrees. Since, real numbers include negatives then the answer to this question is -5 degrees
Integrate both sides with respect to <em>t</em> :
∫ d<em>y</em>/d<em>t</em> d<em>t</em> = ∫ -12<em>t</em> ² d<em>t</em>
<em>y(t)</em> = -4<em>t</em> ³ + <em>C</em>
Use the initial condition to solve for <em>C</em> :
5 = -4•0³+ <em>C</em>
<em>C</em> = 5
So
<em>y(t)</em> = -4<em>t</em> ³ + 5
and the answer is D.
Alternatively, you can directly apply the fundamental theorem of calculus:



The interquartile range is 4