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Rudiy27
2 years ago
13

3) Which inequality represents this scenario?

Mathematics
2 answers:
andreev551 [17]2 years ago
5 0

Answer:

w < 3.3

C) w < 3.3

D) w < 3.3

olya-2409 [2.1K]2 years ago
4 0

Answer:   w \le 3.3

=====================================================

Explanation:

w is the weight and it may be no more than 3.3 pounds. This is the same as saying that 3.3 pounds is the highest it can go. Think of it as the ceiling.

w = 3.3 is possible or anything smaller than it is possible.

So w is 3.3 or smaller meaning we write the inequality w \le 3.3

The answer is not w < 3.3 because that would exclude 3.3 itself.

The answer is between choices C and D. It seems like one of those inequality signs should have an underline.

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I need to find how many solutions does the system have. ​
REY [17]
From what I got there is one real solution :)

Rearrange the second equation to give y=2-2x, substitute into the first equation to give you a value for x and then using that you can work out y for the exact coordinates of intersection :)

Also they are both straight line graphs so they will either have one or no solutions

Hope this helped :)
4 0
3 years ago
Suppose the claim size of an auto collision insurance, X, is uniformly distributed on the interval $1,000 to $10,000. What is th
timurjin [86]

Answer:

35.35%

Step-by-step explanation:

If there were no deductibles, the expected claim payment would be:

E(X) = \frac{10,000 +1,000}{2} \\E(X) =\$5,500

If the collision insurance claim is under $2,000, then the insurer would not pay anything, but if X > $2,000, then the insurer would pay X - $2,000. The new expected value is:

E_2(X)=\frac{2,000-1,000}{10,000-1,000} *0+\frac{10,000-2,000}{10,000-1,000}*\frac{(2,000-2,000)+(10,000-2,000)}{2} \\E_2(X)=\frac{8}{9}*\frac{0+8,000}{2}\\ E_2(X)=\$3,555.56

The percentage reduction on the claim payment is:

P=(1-\frac{E_2(X)}{E(X)})*100 \\P=(1-\frac{3,555.56}{5,500})*100\\P=35.35\%

There was a 35.35% reduction.

8 0
3 years ago
Which shows a correct order to solve this story problem? Kent and Curtis went to the state fair. They had to pay a total of $7.1
KiRa [710]
The problem is asking how much each person will need to pay. Simplifying the problem into an equation with variables (an algorithm) will greatly help you solve it:

S = Sales Tax = $ 7.18 per any purchase
A = Admission Ticket = $ 22.50 entry price for one person (no tax applied)
F = Food = $ 35.50 purchases for two people

We know the cost for one person was: (22.50) + [(35.50/2) + 7.18] =
$ 47.43 per person. Now we can check each method and see which one is the correct algorithm:

Method A)
[2A + (F + 2S)] / 2 = [ (2)(22.50) + [35.50 + (2)(7.18)] ]/ 2 = $47.43
Method A is the correct answer

Method B)
[(2A + (1/2)F + 2S) /2 = [(2)(22.50) + 35.50(1/2) + (2)7.18] / 2 = $38.55
Wrong answer. This method is incorrect because the tax for both tickets bought are not being used in the equation.

Method C)
[(A + F) / 2 ]+ S = [(22.50 + 35.50) / 2 ] + 7.18 = $35.93
Wrong answer. Incorrect Method. The food cost is being reduced to the cost of one person but admission price is set for two people.
6 0
3 years ago
Please answer correctly !!!!!!!!!!!!!! I will mark Brianliest !!!!!!!!!!!!!!!!
sladkih [1.3K]

Answer:

Step-by-step explanation:

x+165 = 180

x = 180 - 165

x = 15

7 0
3 years ago
The roof of the Terminal Tower is 709 feet above ground. A window washer dropped a bucket from the edge of the roof. How many se
Masja [62]

Answer:

6.64 seconds

Step-by-step explanation:

Given that:

Distance between roof of the terminal and ground = 709 feet

A bucket was dropped from the roof.

To find:

The time taken by the bucket to hit the ground?

Solution:

Distance traveled, s = 709 feet

Initial velocity of the bucket, u = 0 feet/sec (because initially it was at rest)

Acceleration of the bucket will be equal to acceleration due to gravity i.e.

g or 32.1741 ft/sec^{2}

Let the time taken is t seconds.

Formula for distance is given as:

s = ut+\dfrac{1}{2}at^2

Putting all the values:

709 = 0 (t) + \dfrac{1}{2}(32.1741) t^2\\\Rightarrow 1418 = 32.1741 t^2\\\Rightarrow t^2 = 44.07\\\Rightarrow t \approx \bold{6.64\ sec}

6 0
2 years ago
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