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Lynna [10]
3 years ago
13

You know the distance between two cities is 140 miles. What is the distance in kilometers?

Mathematics
2 answers:
Juli2301 [7.4K]3 years ago
7 0
The unknown is the distance in kilometres
The given is the distance in miles=140 miles
1 mile=1.6093km
140 miles=?
140/1*1.6093km=225.302km
Therefore the 140 miles in km is 225.302km
Marysya12 [62]3 years ago
6 0

Answer:

225.302 km.

Step-by-step explanation:

Given :The distance between two cities is 140 miles.

To Find: What is the distance in kilometers?  

Solution:

The distance between two cities = 140 miles

1 mile = 1.6093 km

140 miles = 140 \times 1.6093

               = 225.302

The distance between two cities in km = 225.302 km

Hence the distance in kilometers is 225.302 km.

So, Option C is true .

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For each angle θ listed below, find the reference angle α, and then find sin θ. Round sin θ to four decimal places, if necessary
babunello [35]

Answer with explanation:

It is given that

 \rightarrow\Theta =132^{\circ}

The Angle lies in Second Quadrant.

Formula to find reference Angle

→If Angle lies in first Quadrant

  then Reference Angle = The Angle given

→If Angle lies in Second Quadrant

  Then Reference Angle = 180° - Angle

→If Angle lies in third Quadrant

  then Reference Angle =  Angle - 180°

→If Angle lies in fourth Quadrant

  Then Reference Angle = 360° -Angle

Reference Angle

   =180^{\circ}-132^{\circ}\\\\=48^{\circ}

⇒sin 48°=0.7431448

Rounding to four decimal places

Sin 48°=0.7432

4 0
3 years ago
What is the x-component of the electric field at (x, y) = (0 m, 4 m)??
Elza [17]
(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.

What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.

What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.

What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?

(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.
8 0
3 years ago
(5,6) and (−5,12) what is the rate of change??
Veseljchak [2.6K]

Answer:

- 0.6

Step-by-step explanation:

Start point: (5,6)

End point: (-5,12)

rate of change = (12-6) / (-5-5) = 6/-10 = - 3/5 = - 0.6

4 0
3 years ago
Read 2 more answers
if there are 90 calories in 3/4 cuo of yogurt how man calories are in 3 cups of yogurt 30 calories 202 calories 270 calories 360
Debora [2.8K]
Hello!

To find how many calories in three cups we can use the proportion below.

\frac{calories}{cups} = \frac{90}{3/4} = \frac{c}{3}

To find our answer we can say, "How many times does 3/4 go into 3," and then multiply that number by 90 as shown below.

3÷3/4=4
90(4)=360

Just to verify, we will cross multiply and check our answer 

90(3)÷3/4
270÷3/4=360

Therefore, our answer is D) 360 calories.

I hope this helps!

6 0
3 years ago
Read 2 more answers
Help me asap
pogonyaev

Answer:

6J = 72

Step-by-step explanation:

Because it says the product, it is talking about multiplication.

J would be Jamelle's age

6 is the excess number given.

72 is the answer

thus it would be 6*J or 6J = 72

4 0
2 years ago
Read 2 more answers
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