Answer:
Ok so the area of the frame is 18*12 = 216cm^2
Let’s suppose the width of the frame is x
The total area (painting and frame) is (2x+18)(2x+12) and this is equal to 432
4x^2 + 60x + 216 = 432
4x^2 + 60x - 216 = 0
x^2 + 15x - 54 = 0
(x+18)(x-3) = 0
Therefore x = {-18,3}
Since width of the frame has to be positive, the width has to be 3cm Step-
i hope i helped!
Since in a pass code, the placement of the digits is
important, therefore this means that to solve for the total number of
possibilities we have to make use of the principle of Permutation. The formula
for calculating the total number of possibilities using Permutation is given
as:
P = n! / (n – r)!
where,
n = is the total amount of numbers to choose from = 20
r = is the total number of digits needed in the passcode =
4
Therefore solving for the total possibilities P:
P = 20! / (20 – 4)!
P = 20! / 16!
P = 116,280
<span>Hence there are a total of 116,280 possibilities of pass
codes.</span>
Answer:
3.33 ounces in each bowl
Step-by-step explanation:
7.49 + 6.26 = 13.75
subtract 0.43 and that equals 13.32
13.32 ÷ 4 = 3.33
I hope this helped :/
5/6 or 83% (roughly, since probability is never exact).
(hope this helps!)