(1+y) (4y+6) =0 algebra 2

Solve using the elimination method <br> 0.3x-0.2y=4<br> 0.2x+0.5y=-21/23

Aneli [31]

Do this and then simplify the result

5 0

3 years ago

¿que opinas de las personas que no bautizan a sus hijos?

ioda

Answer:

En el bautismo moderno de un bebé o un niño, el padrino o los padrinos hacen una profesión de fe para la persona que se bautiza (el ahijado) y asumen la obligación de actuar como apoderados de los padres si los padres no pueden o se niegan a mantener. la formación religiosa del niño

6 0

2 years ago

The plot below shows the graphs of three functions, f, g, and h, all of which determine the population of three different cities

monitta

So, here we have an exponential function.

Remember that an exponential function has the form:

$y=a(b)^x=a(1\pm\frac{r}{100})^x$

Where a represents an initial amount, and r is the rate of this amount to change. (Increase, or decrease).

So, given that the population of City A in 2000 was 40 thousand people and the population increased by 13% each year, we can say that

$\begin{gathered} a=40 \\ b=1+\frac{13}{100}=1.13 \end{gathered}$

So,

$f(x)=40(1.13)^x$

For city B:

$\begin{gathered} a=40 \\ b=1+\frac{16}{100}=1.16 \\ g(x)=40(1.16)^x \end{gathered}$

But something different happens with city C. This is not an exponential function, this is a linear function.

So,

$h(x)=40+10x$

7 0

1 year ago

Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3

solmaris [256]

Given:

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

$\sin (u)=-\dfrac{7}{25}$

$\cos (v)=-\dfrac{4}{5}$

Now,

$\cos (u)=-\sqrt{1-\sin^2 (u)}$

$\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}$

$\cos (u)=-\sqrt{1-\dfrac{49}{625}}$

$\cos (u)=-\sqrt{\dfrac{625-49}{625}}$

On further simplification, we get

$\cos (u)=-\sqrt{\dfrac{576}{625}}$

$\cos (u)=-\dfrac{24}{25}$

Similarly,

$\sin (v)=-\sqrt{1-\cos^2 (v)}$

$\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}$

$\sin (v)=-\sqrt{1-\dfrac{16}{25}}$

$\sin (v)=-\sqrt{\dfrac{25-16}{25}}$

$\sin (v)=-\sqrt{\dfrac{9}{25}}$

$\sin (v)=-\dfrac{3}{5}$

Now,

$\cos (u-v)=\cos u\cos v+\sin u\sin v$

$\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)$

$\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}$

$\cos (u-v)=\dfrac{1 17}{625}$

Therefore, the value of cos (u-v) is 0.1872.

6 0

3 years ago

What’s different about solving inequalities when you have to multiply or divide by a negative number? Can you explain why a spec

Sergeu [11.5K]

Alright, let's take an example. 1 is less than 2, so we can write it as 1<2. However, if we multiplied both sides by -1 without changing anything else, we get -1<-2, but -1 is greater than -2 because it is less negative, so the correct way of writing it would be -1>-2. Therefore, since a number that is less positive than another becomes less negative (and therefore higher) when both are multiplied by -1, we have to change the side of the inequality

3 0

3 years ago