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3 years ago

Which set of ordered pairs represents y as a function of x ?

1 answer:

6 0

Your answer is J. To determine this, you can graph this and do the Vertical line test. This is the easiest method to use! When u draw a straight line on the graph and if it hits the line more than once, it is NOT a function of x. Nope this helps!!

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Emma buys packets of coloured beads.

Black_prince [1.1K]

Answer:

5 purple beads

8 red beads

4 blue beads

Step-by-step explanation:

Find the common factor of 8 5 and 10

Which is 40

8 * 5 = 40

5 * 8 = 40

4 * 10 = 40

8 0

3 years ago

If EG = 2u + 9 and EI = 5u - 48, find EI in parallelogram FGHI.

zalisa [80]

Answer:

Step-by-step explanation:

The diagonals of a parallelogram bisect in their middle point, so :

2u + 9 = 5u - 48

3u = 57

u = 19

EI = 5* 19 - 48 = 47

4 0

3 years ago

Find all solutions of the equation algebraically. Use a graphing utility to verify the solutions graphically. (Enter your answer

Anuta_ua [19.1K]

Answer:

The solutions of the equation are 0 and 0.75.

Step-by-step explanation:

Given : Equation $16x^4 - 24x^3 +9x^2 =0$

To find : All solutions of the equation algebraically. Use a graphing utility to verify the solutions graphically ?

Solution :

Equation $16x^4 - 24x^3 +9x^2 =0$

$x^2(16x^2-24x+9)=0$

Either $x^2=0$ or $16x^2-24x+9=0$

When $x^2=0$

$x=0$

When $16x^2-24x+9=0$

Solve by quadratic formula, $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-24)\pm\sqrt{(-24)^2-4(16)(9)}}{2(16)}$

$x=\frac{24\pm\sqrt{0}}{32}$

$x=\frac{24}{32}$

$x=\frac{3}{4}$

$x=0.75$

The solutions of the equation are 0 and 0.75.

For verification,

In the graph where the curve cut x-axis is the solution of the equation.

Refer the attached figure below.

7 0

3 years ago

What is the perimeter of a swimming pool that is 97 feet in length and 17 feet wide?

Lubov Fominskaja [6]

Answer:

228 ft

Step-by-step explanation:

P = 2(l+w)

We know the length is 97 and the width 17

P = 2(97+17)

= 2(114)

=228

6 0

3 years ago

Read 2 more answers

Let u = (1,2), v = (−3,4), and w = (5,0)

sergij07 [2.7K]

Answer:

w-2u-v

Step-by-step explanation:

Given are three vectors u, v and w.

In R^2 we treat first element as x coordinate and 2nd element as y coordinate.

Thus we mark (1,2) in the I quadrant, (-3,4) in II quadrant and (5,0) on positive x axis 5 units form the origin.

b) $w=au+bv$

We have to find the values of a and b

$(5,0) = a(1,2)+b(-3,4)$ ]

Equate the corresponding terms

$5=a-3b\\0=2a+4b$

Divide II equation by 2 to get

$0=a+2b$

Eliminate a

-5 = 5b: b=-1

a=-2

Hence

w = 2u-v

7 0

3 years ago