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Gnesinka [82]
4 years ago
13

Given 11 and 6, which of the following could not be the third side of the triangle?

Mathematics
1 answer:
nata0808 [166]4 years ago
3 0

Answer:

<h3>       Any, that is greater than 5 and less than 17 </h3>

Step-by-step explanation:

Given three sides of triangle: a, b and c, and a<c and b<c, then the triangle exist only if  a+b>c

therefore:

if a = 11 and b = 6 and c = ??

then:  11 + 6 > c

            c < 17

if a = 6 and c = 11 and b = ?? {or b=6 and a=??}

then:  6 + b > 11  {subtract 6 from both sides}

            b > 5

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3 years ago
Determine if each statement is true or false. If the statement is false, explain why, or show work proving that it is false.
kherson [118]

Answer:

a). true

b). true

Step-by-step explanation:

a).

Given : If a = 5, then ac = 5c

            Let c be any constant.

            a = 5 (given)

            Therefore, ac = 5c

Here a  is given a constant value (5), also let assume c to be a constant. So when we multiply each term we will get a constant value of 5c. The ratio does not change.

Hence proved.

b).

Given : If ac = 5c, then a = 5

            Let c be any constant

            It is given, a = 5

Therefore, ac = 5c

Here the product of two terms is given as 5c, where c is assume to be a constant. Then as a product rule, the value of a will be 5. The ratio will not change.

Hence proved.

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3 years ago
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3 years ago
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loris [4]

Answer:

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Step-by-step explanation:

475/15 = 31.666

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3 years ago
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Can someone PLEASE help me. I really don't know...
lyudmila [28]

Hope this helps...feel free to ask for any help

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4 years ago
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