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Gnesinka [82]
3 years ago
13

Given 11 and 6, which of the following could not be the third side of the triangle?

Mathematics
1 answer:
nata0808 [166]3 years ago
3 0

Answer:

<h3>       Any, that is greater than 5 and less than 17 </h3>

Step-by-step explanation:

Given three sides of triangle: a, b and c, and a<c and b<c, then the triangle exist only if  a+b>c

therefore:

if a = 11 and b = 6 and c = ??

then:  11 + 6 > c

            c < 17

if a = 6 and c = 11 and b = ?? {or b=6 and a=??}

then:  6 + b > 11  {subtract 6 from both sides}

            b > 5

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Answer:

~ is for negation

^ is for "and"

v is for "or"

=> for "if then"

<=> for "if and only if"

Step-by-step explanation:

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I didn't win the million dollar jackpot because I didn't buy a lottery ticket this weekend.

(g) ~P ^ ~Q (negation of P is in conjunction with negation of Q)

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(h) ~P v (P ^ Q)

This is logically equivalent to (~P v P) ^ (~P v Q) (negation of P is in disjunction with P, and also with disjunction with Q), and can be best expressed as:

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4 years ago
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Answer:

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