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dmitriy555 [2]
2 years ago
5

1.4 pounds of almonds, 0.8 pound of cashews, and 2.6 pounds of peanuts. How much does Mila spend in all

Mathematics
1 answer:
Delicious77 [7]2 years ago
4 0

Answer:

the total amount spent is $31.68

Step-by-step explanation:

The computation of total amount spent as follows:

= 1.4 pounds × $9.15 + 0.8 pounds × $10.75 + 2.6 pounds × $3.95

= $12.81 + $8.6 + $10.27

= $31.68

hence, the total amount spent is $31.68

We simply apply the pounds with its price

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Simplify each expression. 4(4)(2b)
blondinia [14]

Answer:

32b

Step-by-step explanation:

4(4)(2b)=16(2b)=32b

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3 years ago
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likoan [24]

List of prime numbers: 2,3,5,7,11

Both C and D equal 2 which is a prime number.

The answers are C and D

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3 years ago
Which statement illustrates the Distributive Property of scalar multiplication? (Assume that A and B are matrices and c and d ar
olasank [31]

Answer:

C. cA-cB=c(A-B)

Step-by-step explanation:

Given that A and B are matrices and c is a scalar, then the distributive property of scalar multiplication over addition is given by;

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The distributive property of scalar multiplication over subtraction is

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3 years ago
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What is .0067 .007 .00618 .00701 .006 arranged in largest to smallest
Sidana [21]


00701, .007, .0067, .00618, .006
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5 0
3 years ago
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Virty [35]

Answer:

The equations 3·x - 6·y = 9 and x - 2·y = 3 are the same

The possible solution are the points (infinite) on the line of the graph representing the equation 3·x - 6·y = 9 or x - 2·y = 3 which is the same line

Step-by-step explanation:

The given linear equations are;

3·x - 6·y = 9...(1)

x - 2·y = 3...(2)

The solution of a system of two linear equations with two unknowns can be found graphically by plotting the two equations and finding the coordinates of the point of intersection of the line graphs

Making 'y' the subject of both equations gives;

For equation (1);

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3·x - 9 = 6·y

y = x/2 - 3/2

For equation (2);

x - 2·y = 3

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y = x/2 - 3/2

We observe that the two equations are the same and will have an infinite number of solutions

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