There is no way that the amount of cars and trucks can evenly fit into the 270 minutes and $150.
The closet i got was
A) 6 trucks and 4 cars for $150 and 390 minutes
B) 2 trucks and 10 cars for $150 and 380 minutes
C) 3 trucks and 5 cars for $105 and 270 minutes.
Interpreting your expression as

when
approaches zero, the numerator approaches 3:

The denominator approaches 0, because 
Moreover, we have

So, the limit does not exist, because left and right limits are different:

Answer:
25
Explanation:
In order to solve this the easiest way you can use equivalent fractions.

Since 4 times 5 equals 20 we can multiply 5 times 5 to get our answer.

25 is the answer. But, if we couldn't have gotten to 20 through the multiplication we could use a proportion. That would look like the initial problem but instead of a "?" we would use a variable. I will use <em>t</em> for total.

So now we have our problem set up. The next step is to cross multiply. 4 by <em>t</em> and 5 by 20.

And now we can solve it like a normal algebra problem.

Either way, we get 25.
Answer:
Son's age = 24 years
Man's age = 48 years
Step-by-step explanation:
Let's take the age of son as x
Man's age = 2x
Twelve years ago,
Son's age= x-12
Man's age= 2x-12
Man is three times as old as his son so,

Solving for x,
2x-12(1) = x-12(3)
2x-12 = 3x-36
2x-3x = -36+12
-x = - 24
x = 24
So if we substitute the values we get,
Son's age = 24 years
Man's age = 48 years
Hope you understand :)