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ELEN [110]
3 years ago
5

People who suffer from attention-deficit/hyperactivity disorder (adhd) tend to have unusually low levels of ___________. select

one:
a. dopamine
b. epinephrine
c. norepinephrine
d. gamma-aminobutyric acid (gaba)
Biology
2 answers:
Semmy [17]3 years ago
8 0
People who suffer from attention-deficit/hyperactivity disorder (ADHD) tend to have unusually low levels of dopamine.  
<span>
ADHD is a brain disorder characterized by problems in paying attention and excessive activity and it is suggested that lower levels of dopamine (elevated number of dopamine transporters) are associated with symptoms of ADHD. ADHD is associated with functional impairments of dopamine pathways and also norepinephrine pathways because these pathways are responsible for modulating <span>executive function<span> (cognitive control of behaviour).</span></span></span>
Oksanka [162]3 years ago
3 0
GABA

GABA is a neurotransmitter which helps in the inhibition of signals in the central nervous system. GABA blocks the nerve impulse so the neurons will not fire too often. This is also important in maintaining muscle tone. It is speculated that people with ADHD has GABA deficiency. The inadequacy of GABA can lead to insomnia, depression, mood swingsm aggression, irritability and other problems.
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adoni [48]

<u>Answer</u>:

  • The possible genotypes of the children are Hh and hh.
  • The probability of genotype Hh = 1/2
  • The probability of genotype hh = 1/2

<u>Explanation</u>:

  • <em>Autosomal genes</em> are the genes present on any of the chromosomes except the sex chromosomes.
  • An autosomal recessive mutation is the mutation in an autosomal gene which only expresses itself in the phenotype in homozygous condition and affects both males and female equally.
  • For the given question, let the autosomal gene be represented by H (dominant) and h (recessive)
  • According to the question,

Since the <em>mother</em> is homozygous her genotype would be hh and the <em>father</em> is heterozygous so his genotype would be Hh.

The following cross is made to know the genotypes of the children :

hh X Hh--------> Hh Hh hh hh

So the <em>possible genotypes of the children are Hh and hh as shown in the cross. </em>

Note : An image is attached representing the cross in a Punnett square.

  • The probability of an event = No. of favourable outcomes/total no. of outcomes

The probability of occurrence of genotype Hh would be = 2/4 = 1/2

Similarly, the probability of occurrence of genotype hh would be 2/4 = 1/2



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