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3 years ago

I will be really happy if you help me out! :)

Mathematics

1 answer:

kykrilka [37]3 years ago

7 0

Answer/Step-by-step explanation:

#8. Using the geometric mean theorem formula, h = √xy, where,

h = x

x = 4 and y = 16

Plug in the values

x = √(4*16)

x = 8

#9. Using the geometric mean formula, h = √xy, where,

h = y

x = 5 and y = 8

Plug in the values into the formula:

y = √(5*8)

y = √40

y = 6.3 (nearest tenth)

#10. Using the geometric mean formula, h = √xy, where,

h = 18

x = 12 and y = y = ???

Plug in the values into the formula:

18 = √(12*y)

Square both sides

18² = 12y

324 = 12y

Divide both sides by 12

27 = y

y = 27

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3 years ago

What are the solutions to the equation x2 = 289?

artcher [175]

Because this is a second degree equation you will have 2 solutions. When you take the square root of a number you have to account for both the positive and negative roots. Since the square root of 289 is 17 then your solutions are +17 and -17.

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4 years ago

Zander read 13 3/4pages in 1/4 of an hour. Sydney read 43 1/3 pages in 2/3 of an hour. At these rates, would Zander or Sydney re

kakasveta [241]

Answer:

At these rates Sydney read 10 pages per hour more than Zander.

Step-by-step explanation:

Zander read $13\frac{3}{4}$ pages in $\frac{1}{4}$ of an hour.

Therefore, pages read by Zander in 1 hour = $\frac{\text{Total pages read}}{\text{Total time taken}}$

= $\frac{13\frac{3}{4}}{\frac{1}{4}}$

= $\frac{55}{4}\times \frac{4}{1}$

= 55 pages per hour

Sydney read $43\frac{1}{3}$ pages in $\frac{2}{3}$ of an hours.

Pages read by Sydney in 1 hour = $\frac{43\frac{1}{3}}{\frac{2}{3} }$

= $\frac{130}{3}\times \frac{3}{2}$

= 65 pages per hour

Therefore, number of pages read more by Sydney as compared to Zander,

= 65 - 55

= 10 pages per hour

At these rates Sydney read 10 pages per hour more than Zander.

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3 years ago

A consumer organization estimates that over a 1-year period 20% of cars will need to be repaired once, 8% will need repairs

Sladkaya [172]

Answer:

Probability that a car need to be repaired once = 20% = 0.20

Probability that a car need to be repaired twice = 8% = 0.08

Probability that a car need to be repaired three or more = 2% = 0.02

a) If you own two cars what is the probability that neither will need repair?

Probability that a car need to be repaired once , twice and thrice or more= 0.20+0.08+0.02=0.3

Probability that car need no repair = 1-0.3=0.7

Neither car will need repair= $0.7 \times 0.7=0.49$

b) both will need repair?

Probability both will need repair = $0.3 \times 0.3=0.09$

c)at least one car will need repair

Neither car will need repair= $0.7 \times 0.7=0.49$

Probability that at least one car will need repair= 1-0.49 = 0.51

6 0

3 years ago

Between what two integers does 98 fall between

Nat2105 [25]

Answer: 99 and 97

Step-by-step explanation: If you make a numberline and write the numbers 90 through 100. 98 is in between integers 99 and 97.

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3 years ago