Heya !
Using a theoram about triangles ,
Given a triangle ∆ABC, the sum of the lengths of any two sides of the triangle is greater than the length of the third side ,
Also , the length of third side always greater than absolute difference of the other two sides ,
Let the third side be x ,
So , x < 9 + 8 and x > 9 - 8
x < 17 and x > 1
Hence , x ∈ [ 2 , 17 ] inch.
Above case is true for any triangle , be it scalene , Isosceles , Right-angled ...
As , for Isosceles , the third side can be 8 or 9 inches ,
For scalene , all values in the above range satusfies ,
For right angled triangle , we have 2 cases ,
Case 1 : Third side is the hypotenuse
Then , x = √(9²+8²) = √145 = 12.0415 inch.
Case 2 : Third side is not the hypotenuse
Then , x = √(9²-8²) = √17 = 4.1231 inch.
Hope it helps you ! :)
Okay so student 2 is correct
Student one is wrong because
The student didn’t multiply by correctly
And student 3 -5(-2) its +10 not -10
Answer:
1/3
Step-by-step explanation:
The ratio is undefined at x=0, so we presume that's where we're interested in the limit. Both numerator and denominator are zero at x=0, so L'Hôpital's rule applies. According to that rule, we replace numerator and denominator with their respective derivatives.
Answer:
<u>x = 6, length = 8 cm and width = 7 cm</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Area of a rectangle = 56 cm²
Length of the rectangle = x + 2
Width of the rectangle= 2x - 5
2. Solve for x. Round to the nearest whole number.
Area of a rectangle = Length * Width
(x + 2) (2x - 5) = 56
2x² + 4x - 5x -10 = 56
2x² - x - 66 = 0
Factoring, we have:
(2x + 11) * (x - 6) = 0
x₁ = 2x + 11 = 0 ⇒ 2x = -11; x₁ = - 5.5
x₂ = x - 6 = 0 ⇒ x₂ = 6
We picked x₂ because x₁ will give us negative values for length and width.
Length = 6 + 2 = 8 cm
Width = 2 * 6 - 5 = 12 - 5 = 7 cm
