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kotegsom [21]
3 years ago
8

How many solutions does this system of equations have? infinitely many exactly two exactly one none

Mathematics
2 answers:
Damm [24]3 years ago
7 0

Answer:

There is exactly one.

Step-by-step explanation: I know a lot of people say this but, i'm from k12 and got this answer correct.

VARVARA [1.3K]3 years ago
6 0
I think it has exactly two
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I need help ASAP!!!
Vera_Pavlovna [14]

I am 99% sure it’s B

6 0
3 years ago
What is the LCD of 2/5 and 1/10 ?
guajiro [1.7K]
The answer is 10 because 5×2 is 10 and 10 times one is 10. So that's the lowest common denominator her.
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3 years ago
A basketball player made 17 out of 20 free throws at practice. What percent of the free throws did the player make? [Write the n
saw5 [17]
He made 81.5% of the throws at practice
6 0
2 years ago
What is the product of (2x-7) and (3x + 3)?
eduard
<h3>✒️EVALUATION </h3>

==================================

\large\sf\underline{Problem:}

What is the product of (2x-7) and (3x + 3)?

  • A. 6x2 + 15x-21
  • B. 6x2 - 15x - 21
  • C. 6x2 + 15x + 21
  • D. 6x2 - 15x + 21

==================================

\large\sf\underline{Answer:}

\qquad \qquad \huge \rm Letter\:B.

*Please read and understand my solution. Don't just rely on my direct answer*

==================================

\large\sf\underline{Solution:}

Here we have the given choices:

  • A. 6x2 + 15x-21
  • B. 6x2 - 15x - 21
  • C. 6x2 + 15x + 21
  • D. 6x2 - 15x + 21

Solve this equation using the distributive property,where you multiply each term to get the number.

\begin{gathered} \rm2x - 7 = \boxed{ 6} \: \bigg| \small\boxed{\: 6 {x}^{2} } \\ \rm (7)(3) = \boxed{21} \bigg | \boxed{\: 21 x} \\ \\ \qquad \rm6x^{2}+(6x- 21x)-21 \\ \qquad \boxed{ \rm6 {x}^{2} + 15x - 21}\end{gathered}

Therefore, the correct option is letter B.

==================================

ヾ(^-^)ノ

3 0
2 years ago
HERE HELP PLEASE<br> plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz
nevsk [136]
A function is a relation for which each value from the set the first components of the ordered pairs is associated with exactly one value from the set of second components of the ordered pair.
3 0
2 years ago
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