Step-by-step explanation:
-74+36.2=-37.8
I hope it will help you
<span>the formula that I used would be
p = a √( 2 - 2 cos(A) ) = a √( 2 + 2 cos(B) )q = a √( 2 + 2 cos(A) ) = a √( 2 - 2 cos(B) )<span>p2 + q2 = 4a2
this would give us these measurements for the diagonals
p=9
q=15</span></span>
A) You want to find t such that
.. C(t) = d
.. d = 20 +60*0.95^t
.. (d -20)/60 = 0.95^t
.. log((d -20)/60) = t*log(0.95)
.. t = log((d -20)/60)/log(0.95) . . . . . . time to cool to d degrees (d > 20)
b) C'(t) = 60*0.95^t*ln(0.95)
.. C'(1) = 60*0.95*ln(0.95) ≈ -2.924 °C/min
Answer: 70.77 or 71 if rounded up
Step-by-step explanation:
Add all the scores then divide to 18.
The main formula of a suface area of a cube is as follow:
A = 6x a², where a is the edge length
if a= 1.5, so A= 1.5² x 6= 13.5
so the answer is A= <span>13.5</span>
