Answer is in the file below
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Let the speed for the first 12 mi be x mi/h, the speed for 18 mi was (x+4) mi/h
thus given that
time=distance/speed
the average time will be:
3=(12+18)/(x+x+4)
3=30/(2x+4)
solving for x we get
3(2x+4)=30
6x+6=30
6x=24
x=4 mi/hr
Answer: 12 mi/hr
Answer:
9
Step-by-step explanation:
2*2=4*2=8+2=10-1=9
Answer:
should be 192
Step-by-step explanation: