Intercepts<span> occur when a line crosses the </span>x<span>-axis or the </span>y<span>-axis. When the line crosses the </span>x<span>-axis, then </span>y<span> = 0 and </span>x<span> = </span>3<span>. ... The </span>intercept<span> points are (0, 4) and (</span>3<span>, 0 ). So the </span>y-intercept<span> is 4 and the </span>x intercept<span> is </span>3<span> and the sum is 7.</span>
Tan²( θ ) - (1 + √3) tan (θ) + √3 = 0
tan²( θ ) - (tan (θ) + √3 tan (θ)) + √3 = 0
tan²( θ ) - tan (θ) - √3 tan (θ) + √3 = 0
tan( θ ) ( tan (θ) - 1) - √3 ( tan (θ) - 1 ) = 0
( tan( θ ) - 1 ) ( tan( θ ) - √3 ) = 0
tan( θ ) - 1 = 0
θ = π/₄
tan( θ ) - √3 = 0
θ = π/₃
so θ = π/₄ and θ = π/₃
1st way- 3^2 * 3^3
2nd way- 3 * 3^4
3rd way- 3^0 * 3^5
<u>Answer (1):</u>
Coefficient of any term means the number multiplied in that term including sign.
is same as 
.
Hence required coefficient is 1.
<u>Answer (2):</u>
Hence final answer is 166
<u>Answer (3):</u>
Hence final answer is 
Answer:
x = 3 and -2 are the two solutions.
Step-by-step explanation:
2x^2 -2x -12 = 0
First factor out a 2
2(x^2 - x - 6) = 0
2(x - 3)(x + 2) = 0
2 = 0 x - 3 = 0 x + 2 = 0
2 does not equal zero so this is an extraneous solution
x - 3 = 0 so x = 3
x + 2 = 0 so x = -2
