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3 years ago

On a coordinate plane, points (2, 4), (4, 8), and (5, 10) are plotted.

Mathematics

2 answers:

zheka24 [161]3 years ago

5 0

Answer:

B.) The three points lie on a straight line.

C.) A line through the points passes through the origin.

E.) The graph shows a proportional relationship.

Step-by-step explanation:

mario62 [17]3 years ago

4 0

Step-by-step explanation:

(2, 4), (4, 8) and (5, 10) are on the line y = 2x.

Hence they line on a straight line,

The line passes through the origin, and

it shows a proportional relationship.

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Use pi=3.14 to estimate the circumference of the circle to the nearest hundreth the diameter is 11 cm

TiliK225 [7]

The formula of circumference: 兀×diameter

In this case:

3.14×11
=34.54cm

Nearest hundreth = 2 demical places

Therefore, the answer is 34.54cm.

Hope it helps!

3 0

3 years ago

The midpoint of AB is M(3,3). If the coordinates of A are (2,-8), what are the coordinates of B?

Lyrx [107]

Step-by-step explanation:

MID POINT =[(X1 +X2)/2 , (Y1 +Y2)/2]

WE KNKW THAT A(2,–8) AND THE MID POINT IS (3,3)

SUBSTITUTING INTO THE EQUATION ABOVE

(3,3) = [(2+ X2)/2 ,(–8+ Y2)/2]

EQUATING THE X COORDINATES

=> 3 = (2+ X2)/2 (CROSS MULTIPLY)

=> 6 = 2 + X2

X(subscript 2)= 4

EQUATING THE Y COORDINATES

=> 3 =(–8 +Y2)/2 (CROSS MULTIPLY)

6 = –8 +Y2

=> Y(subscript 2)= 14

THEREFORE THE COORDINATES OF B ARE (4 ,14)

hope this helps :)

4 0

3 years ago

I don't get this can someone help me with this

kati45 [8]

P= $48c + $17.76 hope this helps

8 0

3 years ago

How much would $300 invested at 7% interest compounded continuously be

Paha777 [63]

The correct awnser would be B because it is the only one rounded to the nearest cent

4 0

2 years ago

Read 2 more answers

A student takes a driving test until it is passed.

Leya [2.2K]

Answer:

The probability that the test is taken an even number of times is 0.30.

Step-by-step explanation:

The probability that a student passes the driving test at any attempt is,

<em>p</em> = 4/7.

The event of a student passing in any attempt is independent of each other.

The probability that the test is taken an even number of times is:

P (even number of tests) = P (Passing in the 2nd attempt)

+ P (Passing in the 4th attempt)

+ P (Passing in the 6th attempt) ...

If a student passed in the 2nd attempt it implies that he failed in the first.

Then, P (Passing in the 2nd attempt) = $(\frac{3}{7}) \times (\frac{4}{7})$

Similarly, P (Passing in the 4th attempt) = $(\frac{3}{7})^{3} \times (\frac{4}{7})$ , since he failed in the first 3 attempts.

And so on.

Compute the probability of an even number of tests as follows:

P (even number of tests) = $(\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...$

The result follows a Geometric progression for infinite values.

The sum of infinite GP is:

$S=\frac{a}{1-r^{2}}$

The probability is:

P (even number of tests) = $(\frac{3}{7}) \times (\frac{4}{7})+(\frac{3}{7})^{3} \times (\frac{4}{7})+(\frac{3}{7})^{5} \times (\frac{4}{7})+...$

$=\frac{(\frac{3}{7})(\frac{4}{7} ) }{1-(\frac{3}{7})^{2}}\\=\frac{12}{49}\times\frac{49}{40}\\ =\frac{12}{40}\\ =0.30$

Thus, the probability that the test is taken an even number of times is 0.30.

7 0

3 years ago