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morpeh [17]
2 years ago
8

Help this is 16 points

Mathematics
1 answer:
andre [41]2 years ago
4 0

Answer:

C; 1/2

Step-by-step explanation:

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11+102 +73 = 186 total killed for ivory = 186 Total killed 19 + 129 + 139 = 287. What percent of the total elephants killed does
Kaylis [27]

Answer:

64.8% of elephants were killed for ivory

Step-by-step explanation:

divide the number of elephants killed for ivory by the total number of elephants killed: 186÷287= 0.6780

multiply your answer by 100 to get a percentage: 0.6780 x 100= 67.8%

4 0
3 years ago
A bowl of Halloween candy has 17 Kit-Kats, 23 Hershey bars, 11 Starbursts, and 14 Skittles packets.
gladu [14]

Answer:

a.) 8/13 = 0.6154.

b) 11/65 = 0.1692

c.) 0.0267

d.) 0.0222

Step-by-step explanation:

firstly, we determine total number of candies.

17 kit kat(K)+ 23 hershey(H) + 11 starburst(B) + 14 skittles(S) = 65 candies.

Since, Probability = favourable outcome / possible outcome.

With replacement,

a.) probability of chocolate candy (kitkat or hershey) = 17/65 or 23/65

= 17/65 + 23/65

=40/65 = 8/13

b.) probability of selecting a starburst = 11/65

When without replacement:,

c) 2 kit kats, 1 skittles as first three picks and one chocolate candy as the last pick, = [KKSK], [KSKK], [SKKK], [KKSH], [KSKH], [SKKH]

[(17/65 * 16/64 * 14/63 * 15/62) × 3] + [(17/65 * 16/64 * 14/63 * 23/62) ×3]

Note: first bracket and fourth brackets are multiplied by 3 because the value of the first bracket is same for the first three brackets and the second three brackets also have the same values.

Re:chocolate candy means either KitKat or Hershey.

=[(51720/16248960) × 3] + [(87584/16248960) ×3]

=0.0105 +0.0162

= 0.0267.

d.) 1 kitkat, 1 skittles and 1 hershey as first 3 picks and one Starburst as the last pick.

= [KSHB], [KHSB], [SKHB], [SHKB], [HKSB], [HSKB]

= [(17/65 * 14/64 * 23/63 * 11/62) × 6]

note: multiplied by 6 because we will have the same value for all 6 brackets

= 60214/16248960 * 6

= 0.0222.

5 0
3 years ago
The 2s in 202 how many times greater
Vlad1618 [11]

Answer:

101

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Let R be a relation on the set of all lines in a plane defined by (l 1 , l 2 ) R line l 1 is parallel to l 2 . Show that R is
MArishka [77]

Answer: hello your question is poorly written below is the complete question

Let L be the set of all lines in XY plane and R be the relation in L defined as R = {(L1, L2): L1 is parallel to L2}. Show that R is an equivalence relation. Find the set of all lines related to the line y = 2x + 4.

answer:

a ) R is equivalence

b) y = 2x + C

Step-by-step explanation:

<u>a) Prove that R is an equivalence relation </u>

Every line is seen to be parallel to itself ( i.e. reflexive ) also

L1 is parallel to L2 and L2 is as well parallel to L1 ( i.e. symmetric ) also

If we presume L1 is parallel to L2 and L2 is also parallel to L3 hence we can also conclude that L1 is parallel to L3 as well ( i.e. transitive )

with these conditions we can conclude that ; R is equivalence

<u>b) show the set of all lines related to y = 2x + 4 </u>

The set of all line that is related to y = 2x + 4

y = 2x + C

because parallel lines have the same slopes.

5 0
3 years ago
Drag the operator to the correct location on the image.
timama [110]

Answer:

Thanks you

Step-by-step explanation:

8 0
3 years ago
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