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zepelin [54]
3 years ago
13

Please help! i don't know what to do, my formulas are not working for me. If anyone could please help i would really appreciate

it. also if you do help me could you please list the formulas in the answer?
Complete the steps to find the surface area of the cylinder.

The radius is 3, the height is 4

The area of the base is _____ Pi in.2
The circumference of the base is ____ Pi in.
The area of the lateral surface is ✔ 24 Pi in.2
The surface area is _____ Pi in.2
Mathematics
1 answer:
Burka [1]3 years ago
6 0

Answer:

  • The radius is r = 3 in,
  • The height is h = 4 in

<u>The area of the base:</u>

  • A(b) = πr² = π(3²) = 9π in²

<u>The circumference of the base:</u>

  • C = 2πr = 2π(3) = 6π in

<u>The area of the lateral surface:</u>

  • A(l) = Ch = 6π(4) = 24π in²

<u>The surface area:</u>

  • S = 2A(b) + A(l) = 2*9π + 24π = 42π in²
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A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.
mezya [45]
1. Divide wire b in parts x and b-x. 

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= \frac{1}{2}sin60^{o}side*side=   \frac{1}{2} \frac{ \sqrt{3} }{2}  (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}
A=\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2}  )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

 2 \pi r=x

so r= \frac{x}{2 \pi }

Area of circle = \pi  r^{2}= \pi  ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2}  }* x^{2} = \frac{1}{4 \pi } x^{2}

4. Let f(x)=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)=\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b

x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

6. So one part is \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) } and the other part is b-\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

4 0
3 years ago
Read 2 more answers
Compare the functions shown below: g(x) f(x) = −6x − 3 cosine function with y intercept at 0, negative 3 h(x) = 2 cos(x + π) − 1
anastassius [24]

Answer:

because of the product

Step-by-step explanation:

8 0
3 years ago
What is 5 multiplied by 4 5/6 as a mixed number or a fraction
Anestetic [448]

ANSWER:   24 1/6


Hope That Helps

7 0
3 years ago
Round 9.17302 to the nearest thousandths tenths and nearest unit
statuscvo [17]

Answer:

170000

Step-by-step explanation:

17000

4 0
3 years ago
The length of a rectangle is 8 centimeters. what is the width?​
topjm [15]

Answer:

This is a very vague question. We can't find out the width if it doesn't tell us the area. Comment on my answer the area and I can help.

7 0
3 years ago
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