All categories

2 years ago

When a cell is not ready to divide, it will enter __________.

2 answers:

8 0

Answer: Other types of cells divide slowly or not at all. These cells may exit the G 1start subscript, 1, end subscript phase and enter a resting state called G 0start subscript, 0, end subscript phase. In G 0start subscript, 0, end subscript, a cell is not actively preparing to divide, it's just doing its job.

Explanation:

skelet666 [1.2K]2 years ago

7 0

Answer:

enter a resting state called G 0start subscript

Explanation:

You might be interested in

Tom had 24 cup cakes he gave half of it to nick how many cup cakes did he give to nick

storchak [24]

Answer:

easy answer 12

24 half means 24/2=12

5 0

3 years ago

• nitrogen-fixing • producer • biosphere • consumer • biotic factor • heat • condensation • parasitism • commensalism • neritic

Katarina [22]

Nitrogen-fixing bacteria carry out the conversion of gaseous nitrogen to a biologically useful form of nitrogen
An energy pyramid illustrates that energy in the form of heat is lost to the surroundings as it is passed from one organism to the next
The energy role of a grizzly bear is that of a consumer because it cannot make its own food
Decomposers cycle nutrients from dead organisms back to the soil, where it becomes available for plants
The Savanna biome is characterized by its lack of trees, warm temperatures, and moderate rainfall

Explanation:

The nitrogen-fixing bacteria like Azotobacter which lives in symbiotic relationship in the rhizomes of leguminous plants. They convert inorganic atmospheric nitrogen gas through the action of its enzymes like nitrogenase to organic nitrogen in the form of ammonia, which is readily assimilated by the plants.
In an ecosystem, at each tropic level of an energy pyramid, only 10% of energy is utilized and transferred to the next higher tropic level whereas the majority of energy is dissipated as heat during various metabolic processes.
Decomposers also called saprophytes like earthworms, bacteria, fungi survives on dead and decayed remains of plants and animals and also on fertilizers, pesticides etc in the soil. They recycle the nutrients by breaking down the complex biomolecules into simpler forms and release back into the soil.
Grizzly bears being omnivores eat both plants and animals according to their availability. Hence they are both primary and secondary consumers.
Savanna is a grassland biome with a typical tropical wet and dry climate and receives moderate rainfall. Hence it cannot support trees but only have grasses.

6 0

3 years ago

Correctly order the steps involved cellular immunity:

REY [17]

Answer: B

Explanation:

The T helper cell needs to acttivate the T cyctotoxic cell in order for the Tc cell to go do its work.

Once the TC cell is active it interacts with MHC-1 proteins on the surface of the infected host cell, this allows the Tc cell to recignise the host cell and begin secreting cytotoxins (perforins and granzymes) in order to degrade the infected cell and cause apoptosis (controlled cell death)

5 0

3 years ago

Many soils can be distinguished from other samples by their color and texture. True False

Aneli [31]

the answer is true

i hope i helped

4 0

3 years ago

Read 2 more answers

Considering the same population of cats as in Part A, what is the expected frequency of each genotype (TLTL, TLTS, TSTS ) based

zaharov [31]

Answer:

P = f(TLTL) = 0,16

H = f(TLTS) = 0,48

Q = f(TSTS) = 0,36

Explanation:

Hello!

The allele proportion of any locus defines the genetic constitution of a population. Its sum is 1 and its values can vary between 0 (absent allele) and 1 (fixed allele).

The calculation of allelic frequencies of a population is made taking into account that homozygotes have two identical alleles and heterozygotes have two different alleles.

In this case, let's say:

f(TL) = p

f(TS) = q

p + q = 1

Considering the genotypes TLTL, TLTS, TSTS, and the allele frequencies:

TL= 0,4

TS= 0,6

Genotypic frequency is the relative proportion of genotypes in a population for the locus in question, that is, the number of times the genotype appears in a population.

P = f(TLTL)

H = f(TLTS)

Q = f(TSTS)

Also P + H + Q = 1

And using the equation for Hardy-Weinberg equilibrium, the genotypic frequencies of equilibrium are given by the development of the binomial:

$p^{2} = f(TLTL)$

$2pq = f(TSTL)$

$q^{2} = f(TSTS)$

So, if the population is in balance:

$P = p^{2}$

$H = 2pq$

$Q = q^{2}$

Replacing the given values of allele frecuencies in each equiation you can calculate the expected frequency of each genotype for the next generation as:

$f(TLTL) = P = p^{2} = 0,4^{2} = 0,16$

$f(TLTS) = H = 2pq = 2*0,4*0,6 = 0,48$

$f(TSTS) = Q = q^{2} = 0,6^{2} = 0,36$

I hope you have a SUPER day!

6 0

3 years ago