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tino4ka555 [31]
2 years ago
10

Solve for x. + 6 = 10 4 1 16 64

Mathematics
2 answers:
RUDIKE [14]2 years ago
5 0

ANSWER: x = 16

SOLUTION:

1) Multiply both sides of the equation by 4:

x/4 + 6 = 10 ------> x + 24 =40

2) Move the constant (+ 24) to the right-hand side and change its sign:

x = 40 - 24

3) Subtract the numbers:

x + 16 (simplified)

Alecsey [184]2 years ago
4 0

Answer: First, turn the mixed fraction 16 1/4 into a improper fraction. It would become 65/4

x+65/4=64

Next, I would multiply the entire equation by 4 to get rid of the fraction

It would become 4x+65=256

Now solve for X

4x=191

x=191/4

x=47.75

Step-by-step explanation:

You might be interested in
The function h(t) = -16t^2 + 16t represents the height (in feet) of a horse (t) seconds after it jumps during a steeplechase.
Vladimir79 [104]
A.) To find the maximum height, we can take the derivative of h(t). This will give us the rate at which the horse jumps (velocity) at time t.

h'(t) = -32t + 16

When the horse reaches its maximum height, its position on h(t) will be at the top of the parabola. The slope at this point will be zero because the line tangent to the peak of a parabola is a horizontal line. By setting h'(t) equal to 0, we can find the critical numbers which will be the maximum and minimum t values.

-32t + 16 = 0

-32t = -16

t = 0.5 seconds

b.) To find out if the horse can clear a fence that is 3.5 feet tall, we can plug 0.5 in for t in h(t) and solve for the maximum height.

h(0.5) = -16(0.5)^2 + 16(-0.5) = 4 feet

If 4 is the maximum height the horse can jump, then yes, it can clear a 3.5 foot tall fence.

c.) We know that the horse is in the air whenever h(t) is greater than 0. 

-16t^2 + 16t = 0

-16t(t-1)=0

t = 0 and 1

So if the horse is on the ground at t = 0 and t = 1, then we know it was in the air for 1 second.
7 0
3 years ago
Given the linear equation 5x+3y-9=0. Write another linear equation in two variables such that the geometrical representation of
just olya [345]

Answer:5x+3y+1=0

Step-by-step explanation:

Given

The linear equation is 5x+3y-9=0

The other linear equation parallel to the given line can be represented by

5x+3y+c=0

Here, c can take any value . for example c=1, line becomes

\Rightarrow 5x+3y+1=0

8 0
3 years ago
GUYS PLEASE HELP ME HELP HELP PLEASE PLEASE!!! Simplify and solve for the unknown. Use order of operations as needed. Check your
grandymaker [24]

The solution is B = 43

Step-by-step explanation:

Simplify and solve for the unknown for 5(B + 3) = 4(B - 7) + 2B

  • Simplify each side
  • Add the like terms in each side if need
  • Separate the unknown in one side and the numerical term in the other side to find the value of the unknown

∵ 5(B + 3) = 4(B - 7) + 2B

- Multiply the bracket (B + 3) by 5 in the left hand side and multiply

  the bracket (B - 7) by 4 in the right hand side

∵ 5(B + 3 ) = 5(B) + 5(3) = 5B + 15

∵ 4(B - 7) = 4(B) - 4(7) = 4B - 28

∴ 5B + 15 = 4B - 28 + 2B

- Add the like terms in the right hand side

∵ 4B + 2B = 6B

∴ 5B + 15 = 6B - 28

- Add 28 to both sides

∴ 5B + 43 = 6B

- Subtract 5B from both sides

∴ 43 = B

- Switch the two sides

∴ B = 43

To check the answer substitute the value of B in each side if the two sides are equal then the solution is right

The left hand side

∵ 5(43 + 3) = 5(46) = 230

The right hand side

∵ 4(43 - 7) + 2(43) = 4(36) + 86 = 144 + 86 = 230

∴ L.H.S = R.H.S

∴ The solution B = 43 is right

The solution is B = 43

Learn more:

You can learn more about the solution of an equation in brainly.com/question/11229113

#LearnwithBrainly

7 0
3 years ago
#9) PLEASE HELP WITH QUESTION! MARKING BRAINLIEST +POINTS
umka2103 [35]
D) Vertices: (1, -1), (-11, -1); Foci: (-15, -1), (5, -1)

4 0
2 years ago
Hey guys I just wanted to put this out there-
tino4ka555 [31]

ok thank you so much for the info

5 0
3 years ago
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