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2 years ago

Triangle ABC is transformed to obtain triangle A′B′C′:

Mathematics

1 answer:

Annette [7]2 years ago

7 0

The answer is A because it was dilated by 1/3 and A is the only one that has that

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What are the even<br>numbers less than 18.

Romashka-Z-Leto [24]

Answer:

16,14,12,10,8,6,4,2

Step-by-step explanation:

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3 years ago

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Audrey drew a model to determine how many eighths are in 5.

____ [38]

Answer:

there are 40 eighths in 5

Step-by-step explanation:

40/8 (the fraction)

40÷8=5

is that what the question is asking?

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2 years ago

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Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F

Svet_ta [14]

Answer:

$A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36$

Step-by-step explanation:

The equations are:

$y = x^{2} + 2x + 3$

$y = 2x + 12$

The two graphs intersect when:

$x^{2} + 2x + 3 = 2x + 12$

$x^{2} = 0$

$x_{1} = 3\\x_{2} = -3$

To find the area under the curve for the first equation:

$A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

To find the area under the curve for the second equation:

$A_{2} = \int\limits^3__-3}{2x + 12} \, dx$

To find the total area:

$A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx$

Simplifying the equation:

$A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx$

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).

3 0

2 years ago

Can someone plz help?

vagabundo [1.1K]

your answer is C. substraction

4 0

2 years ago

Hurry Please! :)

Sladkaya [172]

Area = b*h and in some cases * 2 so you need to do this, 64*52 + 40*28= 4448 yd2

8 0

3 years ago

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