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2 years ago

- In what conditions can a factored expression be factored further?

Mathematics

1 answer:

Margarita [4]2 years ago

7 0

When at least one of the factors still has a common factor

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17. x^2 + 2x + 1

valentina_108 [34]

Answer:

E. This polynomial could be factored by using grouping or the perfect squares methods.

Step-by-step explanation:

x^2 + 2x + 1

There is no greatest common factor

This is a perfect square

a^2 + 2ab+ b^2 = ( x+1)^2

We can factor this by grouping

x^2 + 2x + 1

(x^2 +x) + (x+1)

x( x+1) + x+1

Factor out x+1

( x+1) ( x+1)

This is not the difference of squares since there is no subtraction

5 0

3 years ago

Two linear equations are shown. A coordinate grid with 2 lines. The first line is labeled y equals StartFraction one-third EndFr

Lorico [155]

Answer:

$(7,\frac{13}{3})$

Step-by-step explanation:

we have

The equation of the first line

$y=\frac{1}{3}x+2$ ------> equation A

The equation of the second line

$y=\frac{4}{3}x-5$ ------> equation B

Solve the system of equations by elimination

Multiply equation A by -4 both sides

$(-4)y=(-4)(\frac{1}{3}x+2)$

$-4y=-\frac{4}{3}x-8$ --------> equation C

Adds equation B and equation C

$y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}$

Find the value of x

substitute the value of y

$\frac{13}{3}=\frac{1}{3}x+2$

$\frac{1}{3}x=\frac{13}{3}-2$

Multiply by 3 both sides

$x=13-6$

$x=7$

therefore

The solution to the system of equations is the point $(7,\frac{13}{3})$

5 0

2 years ago

Read 2 more answers

solve for the indicated variable. include all of your work in your answer. submit your solution. P=2L+2W; for L.

allochka39001 [22]

We have this equation:

$P=2L+2W$

So, we need to solve this equation for L. Then we sum -2W in each member of the equation, like this:

$P-2W=2L+2W-2W$
$P-2W=2L$

Then, dividing the equation by 2:

$\frac{P-2W}{2}=L$

Finally, let's order this equation:

$L=\frac{P-2W}{2}$

4 0

2 years ago

Simplify 2.1 + (-3.7m) + 1.9m - 1.4

belka [17]

Answer:

-1.8m + 0.7

Step-by-step explanation:

4 0

2 years ago

HELP!!!! Judy has already run 21 miles on her own, and she expects to run 1 mile during each track practice. How many track prac

seropon [69]

It would take 11 track practices for her to run 32 miles!!!