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inysia [295]
3 years ago
13

Two linear equations are shown. A coordinate grid with 2 lines. The first line is labeled y equals StartFraction one-third EndFr

action x plus 2 and passes through (negative 6, 0) and (0, 2). The second line is labeled y equals StartFraction 4 over 3 EndFraction minus 5. What is the solution to the system of equations? (7, 4) (7, StartFraction 13 over 3 EndFraction) (8, StartFraction 14 over 3 EndFraction) (9, 7)
Mathematics
2 answers:
yarga [219]3 years ago
8 1

Answer:

<h2>Its C.</h2>

{8, 14/3}

Lorico [155]3 years ago
5 0

Answer:

(7,\frac{13}{3})

Step-by-step explanation:

we have

<em>The equation of the first line</em>

y=\frac{1}{3}x+2 ------> equation A

<em>The equation of the second line</em>

y=\frac{4}{3}x-5 ------> equation B

Solve the system of equations by elimination

Multiply equation A by -4 both sides

(-4)y=(-4)(\frac{1}{3}x+2)

-4y=-\frac{4}{3}x-8 --------> equation C

Adds equation B and equation C

y=\frac{4}{3}x-5\\-4y=-\frac{4}{3}x-8\\--------\\y-4y=-5-8\\-3y=-13\\y=\frac{13}{3}

<em>Find the value of x</em>

substitute the value of y

\frac{13}{3}=\frac{1}{3}x+2

\frac{1}{3}x=\frac{13}{3}-2

Multiply by 3 both sides

x=13-6

x=7

therefore

The solution to the system of equations is the point (7,\frac{13}{3})

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