Y = kx
80 = 16k
k = 80/16 = 5
direct variation
The first 2 choices are corect
Area for square = s² = 196x¹²y¹⁰z⁶
s = √(<span>196x¹²y¹⁰z⁶)
s = 14x</span>⁶y⁵z³
Perimeter = 4*s = 4*(14x⁶y⁵z³) = 56x<span>⁶y⁵z³
Perimeter = 56</span>x<span>⁶y⁵z³ D</span>
Your answer is 3/5, the picture below shows how sin cos tan work!
Answer:
19ft
Step-by-step explanation:
Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.
The velocity of the ball is zero at maximum height and it is expressed as:
V(x) = dy/dx
V(x) = -32x+32
Since v(x) = 0
0 = -32x+32
32x = 32
x = 32/32
x = 1s
Get the height y
Recall that y = -16x² + 32x + 3.
Substitute x = 1
y = -16(1)²+32(1)+3
y = -16+32+3
y = -16+35
y = 19ft
Hence the maximum height reached by the ball is 19ft
Answer:
0
Step-by-step explanation:
5-5=0
I hope this is correct and have a great day
