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Ahat [919]
3 years ago
9

The table below shows the meal cost and tip for the last 10 tables that a waiter served.

Mathematics
1 answer:
Simora [160]3 years ago
6 0
Can’t see the table:(
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Find the distance between (12,10) and (0,5)
irakobra [83]

Answer:

length = 13

Step-by-step explanation:

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I WILL MAKE YOU BRANLYIST! –(–3) it was on a question and I don't know what to do????
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Answer:

what's your question that you're asking??

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What are the coordinates of the midpoint of the segment whose endpoints are A (-1, -2) and B (6, 12)
Klio2033 [76]

<u>Answer:</u>

Mid point = (\frac{5}{2} ,5)

<u>Step-by-step explanation:</u>

We are given the coordinates of the end points of a line segment AB and we are to find the coordinates of its mid point.

The coordinates of the end points are: A (-1, -2) and B (6, 12).

We know the formula of the mid point:

Mid point = (\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )

So putting in the given values to find the mid point of line segment AB:

Mid point = (\frac{-1+6}{2} ,\frac{-2+12}{2} ) = (\frac{5}{2} ,5)

5 0
3 years ago
Simplify the expression. tan(sin^−1 x)
Blizzard [7]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2799412

_______________


Let  \mathsf{\theta=sin^{-1}(x)\qquad\qquad-\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2}.}

(that is the range of the inverse sine function).


So,

\mathsf{sin\,\theta=sin\!\left[sin^{-1}(x)\right]}\\\\ \mathsf{sin\,\theta=x\qquad\quad(i)}


Square both sides:

\mathsf{sin^2\,\theta=x^2\qquad\qquad(but~sin^2\,\theta=1-cos^2\,\theta)}\\\\ \mathsf{1-cos^2\,\theta=x^2}\\\\ \mathsf{1-x^2=cos^2\,\theta}\\\\ \mathsf{cos^2\,\theta=1-x^2}


Since \mathsf{-\,\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2},} then \mathsf{cos\,\theta} is positive. So take the positive square root and you get

\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\quad(ii)}


Then,

\mathsf{tan\,\theta=\dfrac{sin\,\theta}{cos\,\theta}}\\\\\\ \mathsf{tan\,\theta=\dfrac{x}{\sqrt{1-x^2}}}\\\\\\\\ \therefore~~\mathsf{tan\!\left[sin^{-1}(x)\right]=\dfrac{x}{\sqrt{1-x^2}}\qquad\qquad -1\ \textless \ x\ \textless \ 1.}


I hope this helps. =)


Tags:  <em>inverse trigonometric function sin tan arcsin trigonometry</em>

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Write the expression in words 35-(14 + 17)
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The sum of fourteen and seventeen subtracted from thirty five
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