So first you'll substitute x for -2.3 then you'll subtract 2 by 1 which equals 1 then you'll divide -2.3 on both sides which will equal g = -1.3
Answer:
3x = - 6
Step-by-step explanation:
Three times a number is at most negative six
3 times a number would be 3 times x, is means the equal sign (=)
3x = - 6
Answer:
10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Step-by-step explanation:
In this question, we are tasked with writing the product as a sum.
To do this, we shall be using the sum to product formula below;
cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]
From the question, we can say α= 5x and β= 10x
Plugging these values into the equation, we have
10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]
= 5[sin (15x) - sin (-5x)]
We apply odd identity i.e sin(-x) = -sinx
Thus applying same to sin(-5x)
sin(-5x) = -sin(5x)
Thus;
5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]
= 5[sin (15x) + sin (5x)]
Hence, 10cos(5x)sin(10x) = 5[sin (15x) + sin (5x)]
Answer:
there are 425 numbers of three digits whose the sum of the digits is even.
Step-by-step explanation:
Option 1:
It is necessary to accomplish one of the next conditions:
(1) all of the digits are even.
(2) exactly 2 of the digits are odd
Then, for the first condition:
4x5x5 = 100 -> this is because the first digit can not be 0.
for the second condition:
(3C1)*5*5*5-1*5*5 =3*125-25=350
where 3C1 is a combination. The 3C1 determines which of the three digits is even, and it is necessary to subtract the numbers under 100 with the other 2 digits odd.
So, there are 450 numbers of three digits whose the sum of the digits is even.
Option 2:
there are 900 three digit number and 5*5*5 =125 has 3 odd numbers and 5*5*5+4*5*5+4*5*5=325 has 1 odd number, so there are 450 numbers of three digits whose the sum of the digitis is odd, so 900-450 whose the sum of the digits is even.
