What can you conclude from the box-and-whisker plot?

Explain if 12.1 is rational or irrational

Naddika [18.5K]

It is rational because it is a terminating decimal. It can be represented as a ratio of two integers (121/10)

6 0

2 years ago

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

Let $\bar X$ = sample average time spent studying

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

So, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0

2 years ago

A rectangle is 3 feet longer than it is wide . if the perimeter is 30 feet , find the area in square feet .

noname [10]

Answer:

Hey

Step-by-step explanation:

I beleve you answer is 10 because 3 time 10 equals 30 and the question sais "3 times longer"

5 0

2 years ago

We are told that the two players, taken together, scored a total of 49 points. What is the probability that player A scored firs

mario62 [17]

Answer:

1/2 or 50% probability

Step-by-step explanation:

There are just two players, player A and player B. Since it is between this two players, for player A to score first we would have:

AB where player A is the first player to score, we wouldn't have BA since player would not be the first here

Probability = number of favorable outcomes/total number of outcomes

Therefore probability of A being the first player = number of A/total number of players

=1/2 = 0.50

There is therefore a 50% chance of A being the first player

7 0

2 years ago

Please help ASAP <3 Correct answer gets brainliest :3

Goshia [24]

Answer:

1. 1,016 sq. m.

2. 119 sq. m.

Step-by-step explanation:

1.

14 x 18 = 252

18 x 8 = 144

14 x 8 = 112

2 ( 252 ) + 2 ( 144 ) + 2 ( 112 )

504 + 288 + 224 = 1,016 sq m

2.

4 (7 x 5 divided by 2) + (7 x 7) =

7 x 5= 35 divided by 2 = 17.5 x 4 = 70 + 49 = 119 sq. m.

I hope this helps

sorry if i'm wrong

6 0

2 years ago

What can you conclude from the box-and-whisker plot?​

What can you conclude from the box-and-whisker plot?