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SVETLANKA909090 [29]
2 years ago
13

Calculate the average speed for the following sections on the graph.

Mathematics
2 answers:
Temka [501]2 years ago
5 0

Answer:

a to b is 20m/s I'm in k12 and I got the same question but I don't know for c to d yet

Step-by-step explanation:

A =0

B=200

T=10s

200 divided by 10 is 20m/s

and for the question at the bottom, the answer is c bc c to d is accelerating

Dimas [21]2 years ago
3 0

Answer:

A to B = 2000 m/s

C to D = 30,000m/s

Step-by-step explanation:

A to B is 10secs and the distance is 200m so you multiply them and you get 2000m/s

C to D is 60secs and the distance is 500m so you multiply and you get 30,000m/s

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Step-by-step explanation:

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In the picture below, what is the approximate area that is shaded blue?
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3 years ago
Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 4 at x = −3 and a local minimum value of 0 at
Vinvika [58]
The formula is f(x) = a x ^ 3 + b x ^ 2 + c x  + d 
f '(x) = 3ax^2 + 2bx + c. 
f(- 3) = 3 ==> - 27a + 9b - 3c + d = 3 
f '(- 3) = 0 (being a most extreme) ==> 27a - 6b + c = 0. 
f(1) = 0 ==> a + b + c + d = 0 
f '(1) = 0 (being a base) ==> 3a + 2b + c = 0. 
- 
Along these lines, we have the four conditions 
- 27a + 9b - 3c + d = 3 
a + b + c + d = 0 
27a - 6b + c = 0 
3a + 2b + c = 0 
Subtracting the last two conditions yields 24a - 8b = 0 ==> b = 3a. 
Along these lines, the last condition yields 3a + 6a + c = 0 ==> c = - 9a. 
Consequently, we have from the initial two conditions: 
- 27a + 9(3a) - 3(- 9a) + d = 3 ==> 27a + d = 3 
a + 3a - 9a + d = 0 ==> d = 5a. 
Along these lines, a = 3/32 and d = 15/32. 
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