3 years ago

Need help on the attached question

Mathematics

1 answer:

katen-ka-za [31]3 years ago

4 0

Answer:

f(8) = 4.92`

Step-by-step explanation:

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4=32b<br> solve for b WILL GIVE BRAINLIEST

Makovka662 [10]

Answer:

1/8

Step-by-step explanation:

$32b \div 32 = 4 \div 32 \\$

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2 years ago

Jessies's soccer team won 68% of the games they played. If they won 17 games how many did they play

KengaRu [80]

the answer to your equation is 25, because 17 if 68 is 25

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3 years ago

Helppp i will mark brainliest <3

hodyreva [135]

Answer:

59.8*4=239.2 rounded to the nearest foot is 239

Step-by-step explanation:

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3 years ago

The sides of a triangle are of lengths 13, 14, 1nd 15. the altitude of the triangle meet at point h. if ad is the altitude to th

S_A_V [24]

$\left \{ {{y=2} \atop {x=2}} \right.$

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3 years ago

A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit

m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

$P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792$

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0

3 years ago