Can someone please help me on this one? I will give BRAINLIEST to whoever has the correct answer.
1 answer:
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The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8
<h3><u>Solution:</u></h3>Let "f" be the cost of 1 fries
Let "h" be the cost of 1 hamburger
<em><u>Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24</u></em>
8 x cost of 1 hamburger + 5 x cost of 1 fries = 24
8h + 5f = 24 -------- eqn 1
<em><u>The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60</u></em>
6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60
6h + 2f = 16.60 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Multiply eqn 1 by 2
16h + 10f = 48 ------ eqn 3
Multiply eqn 2 by 5
30h + 10f = 83 -------- eqn 4
<em><u>Subtract eqn 3 from eqn 4</u></em>
30h + 10f = 83
16h + 10f = 48
( - ) ----------------------
14h = 35
<h3>h = 2.5</h3>Substitute h = 2.5 in eqn 1
8(2.5) + 5f = 24
20 + 5f = 24
5f = 4
<h3>f = 0.8</h3>Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8
Answer:
Step-by-step explanation:
Given figure is of a rhombus.
Measures of the opposite angles of a rhombus are equal.
Therefore,
Answer:
1) FALSE
2) FALSE
3) TRUE
4) TRUE
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Part 1
The mean and standard deviation of a normally distributed random variable which has been standardized are one and zero, respectively.
The mean and the deviation for the normal standard distribution are:
So then that's FALSE.
Part 2
Using the standard normal curve, the z−score representing the 10th percentile is 1.28.
We are looking for a value a, that satisfy this:
(a)
(b)
We can find a z value that satisfy the condition with 0.10 of the area on the left and 0.90 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.10 and P(Z>-1.28)=0.90
So that's FALSE.
Part 3
Let z1 be a z−score that is unknown but identifiable by position and area. If the symmetrical area between −z1 and +z1 is 0.9544, the value of z1 is 2.0
If we find this probability:
So on this case we can approximate to 0.9544. And that's TRUE.
Part 4
Using the standard normal curve, the z−score representing the 75th percentile is 0.67.
We are looking for a value a, that satisfy this:
(a)
(b)
We can find a z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.67. On this case P(Z<0.67)=0.75 and P(Z>0.67)=0.25
So that's TRUE.