Answer:
The correct answer is: None of the above. The accurate answer is: Problem or inability in detecting the sensory information.
Explanation:
- Sensory receptor cells form the part of the sensory epithelial layer that are present in the form of a lining in all sensory organs.
- These sensory cells possess some specialised receptor molecules, usually on the surface of the cells, that can sense different types of sensory signals like light, in case of eyes, smell is case of nose, taste in case of tongue and sound in case of ears.
- Any damage caused to these cells will adversely affect their capability to perceive or receive or detect the sensory signals.
- Option I is incorrect because sensory cells are not only present in the eyes and ears but also in nose, tongue, skin. The activity of the sensory cells of one organ is independent of the activity of sensory cells of other organs hence, damage to the sensory cells of one organ will not create any confusion in different sensory inputs.
- Option II is incorrect because integration of all the sensory impulses occur in the brain after the impulse has been received and detected by multiple sensory receptor cells and send to the brain through the sensory neurons.
<span>I is dominant, i is recessive. The A's and B's are just show which allele I is. When there is just one dominant allele, it masks the recessive in blood typing. Remember IA and IB are codominant.
O is always ii
A is IAi (heterozygous) or IAIA (homozygous)
B is IBi (heterozygous) or IBIB (homozygous)
AB is always IAIB
Remember: You get one allele from each parent!
1. Father must be ii, mother must be ii, so all children must be ii.
2. Father is IAIA (the homozygous one), the mother is IBIB, so the only possibility for the children is IAIB, because you get one allele from the father and one from the mother.
3. Father is IAi, mother is IBi, so the children can be any of the blood types, because they can have all the combinations of genotypes.
4. Father is ii, mother is IAIB. Children can only be IAi or IBi.
5. Father is IAIB, mother is IAIB. Children can be IAIA, IBIB, or IAIB.
Example of Punnett square:
3. Father is type A, heterozygous, mother is type B, heterozygous
Father must be IAi (heterozygous)
Mother must be IBi (heterozygous)
_______IA ____ i
IB____ IBIA____IBi
i _____ IAi______ii
Sorry, that was difficult on here, hope it's understandable.
The father's alleles run across the top, the mother's are on the side, you follow to where they meet to find the possibilities for the children. IBIA (AB blood type), IBi (B), IAi (A), and ii (O) are the possibilities in this case.
Hope that helps!</span>
