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lesya692 [45]
3 years ago
9

MY LAST QUESTION PLEASE HELP Find the measures of a and b in the figure.

Mathematics
1 answer:
ankoles [38]3 years ago
4 0

Answer:

55

Step-by-step explanation:

62+63=125

180-125=55

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Plz help fast will mark the brainiest!!!
Kobotan [32]

Answer:

1.5 x 10^0

Step-by-step explanation:

3 0
3 years ago
The volume of the rectangular prism is 648 feet. The rectangular base is 6 feet by 9 feet. What is the height of the prism?
IrinaK [193]

Answer:

h=12ft

Step-by-step explanation:

The formula one would use for finding the volume of a rectangular prism is as follows:

  • Volume = length × width × height , V=l*w*h

With this in mind, let's plug in the given variables in the question for this formula.

V=648ft^3

l=6ft

w=9ft

h= ?

  • We don't know the height, but that's just fine. We will plug in all our values and isolate h.

V=lwh\\648ft^3=(6ft)(9ft)h

  • I'm leaving in units just because I want to show that units aren't just for show. They can be used when in doubt of how to go about your math.

648ft^3=(6ft)(9ft)h\\648ft^3=(54ft^2)h\\\frac{648ft^3}{54ft^2}=\frac{(54ft^2)h}{54ft^2}

  • Notice, that the units on the left side cancel out, leaving only the unit ft left next to the solution. In the same way, the units on the right side cancel out too, leaving only h, height.

\frac{648ft^3}{54ft^2}=\frac{(54ft^2)h}{54ft^2}\\12ft=h

If involving units only confuses you, like it does for me, you can remove them like so, you just need to know what units your solution uses instead of being able to come to the proper units by using math.

V=lwh\\648=(6)(9)h\\648=54h\\\frac{648}{54}=\frac{54h}{54}\\12ft=h

5 0
3 years ago
A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the
amm1812

Answer:

s(t)=(ln|7|+ln|2|)\,ft

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\

Integrating both sides w.r.to t

v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\

Using initial value

v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}

We have to calculate the distance covered in time interval [0,5], so:

\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft

3 0
3 years ago
Can you figure this out? And then show your work plz?
Salsk061 [2.6K]

Step-by-step explanation:

You can use PEMDAS to solve this problem from left to right.

First, do 15 ÷ 3 to get 5.

Next, do 2 x 10 to get 20.

Lastly, add 5 and 20 to get 25.

<u>15 ÷ 3</u> + 2 x 10

5 + <u>2 x 10</u>

<u>5 + 20</u>

25

3 0
3 years ago
Read 2 more answers
Solve the proportion<br> 17/4 = y/6
Tanya [424]

Answer:

This is your answer ☺️☺️

3 0
3 years ago
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