All categories

2 years ago

Hi can someone please help

Mathematics

1 answer:

Blababa [14]2 years ago

3 0

Answer:32

Step-by-step explanation:

You might be interested in

7. Simplify this what’s the answer?

trasher [3.6K]

first the square root of 4 is 2 so we can sub that in.

now we have 2(2*2)^-2.

2 * 2 of course is 4

with 2(4)^-2, keep in mind that negative exponents just mean to "flip" the number and turn the exponents positive.

so 4^-2 is the same as 1/4^2 or 1/16.

finally 1/16 * 2 = 2/16. 2/16 simplified is 1/8.

3 0

3 years ago

Given that cos θ = –12∕13 and θ is in quadrant III, find csc θ.

Trava [24]

Answer:

Step-by-step explanation:

We are given:

$\displaystyle \cos(\theta)=-\frac{12}{13},\,\theta\in\text{QIII}$

Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

$o=\sqrt{13^2-12^2}=\sqrt{25}=5$

So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.

And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

$\displaystyle \csc(\theta)=\frac{13}{5}$

Since θ is in QIII, cosecant must be negative:

$\displaystyle \csc(\theta)=-\frac{13}{5}$

Our answer is A.

7 0

2 years ago

Read 2 more answers

What are all the angle measures for right triangle ABC?

Alenkasestr [34]

Answer:

$\alpha = 60°,\:\beta = 30°, \: 90°$

Step-by-step explanation:

$Arccos( \frac{ \sqrt{3} }{2} ) = \beta \\ Arccos( \cos \: 30 \degree ) = \beta \\30 \degree = \beta \\ \therefore \: \alpha = 60 \degree \\ remaining \: angle = 90 \degree \\$

3 0

2 years ago

Solve the equation -4x+12=-4 for x .

mihalych1998 [28]

-4x +12 -12 = -4 -12
-4x = -16
x = 4

4 0

2 years ago

Read 2 more answers

Help 12 minutes to turn in

NARA [144]

Shows how far day valued asking questions

6 0

2 years ago