Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is 
is correct answer
Therefore ![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2%3D%5Cfrac%7B1%7D%7B3%5E8%7D)
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
( using the property 
)
( using the property 
( combining the like powers )
( using the property 
)
( using the property 
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is is correct answer
Given the slope, m = -2/3, and the x-intercept, (3,0):
Use these values and plug into the slope-intercept form to solve for the y-intercept, b:
y = mx + b
0 = -2/3(3) + b
0 = -2 + b
Add 2 to both sides to isolate b:
0 + 2 = -2 + 2 + b
2 = b
Now that we have our slope, m = -2/3, and the y-intercept, 2
The linear equation in slope-intercept form is:
y = -2/3x + 2
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-1, 0.5, 2/3, 1.1 is the order of the numbers from least to greatest
Yes, it has the same result
look at the picture. the red triangle is the first image. the green one is the result of reflecting over x-axis. then if you reflect it over y-axis, it would be the purple triangle
if you had rotated the red triangle at first, it would have the same result
good luck
2 didved 15 times 2 see what you get that your anwers\
