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2 answers:
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Answer:
a.$7,096
Step-by-step explanation:
- total amount A = s(\frac{(1+\frac{r}{n}) ^{n*t}-1 }{\frac{r}{n} } )[/tex]
[this is the formula used when certain amount is added at regular intervals and if the interest is COMPOUNDED]
(here,
s=deposit added at the end of each quarter= $500
n= number of times interest is compounded per unit 't'=4
t=total time = 3 years
r=interest rate ( expressed in decimal or fraction not in %) = 12/100 = 0.12 )
- A= 500(\frac{(1+\frac{0.12}{4}) ^{4*3}-1 }{\frac{0.12}{4} } )[/tex]
- by solving further,
A
( [1.03]^12= 1.42576 ( approximately) { use calculator for exact values})
18 + 46 = 64
See image
6s into 6 = 1
6s into 4 = 0 - carry the 4 over to the next space
6s into 40 = 6 remainder 4 - carry the 4
6s into 40 = 6 remainder 4 - carry the 4
4 will become repeatedly carried (an infinite number of times) so we call it a recurring number. This can be shown by a number (in this case 6) with a dot above it.
(18 + 46)/6 = 10.666... or 10.67
See image
6s into 6 = 1
6s into 4 = 0 - carry the 4 over to the next space
6s into 40 = 6 remainder 4 - carry the 4
6s into 40 = 6 remainder 4 - carry the 4
4 will become repeatedly carried (an infinite number of times) so we call it a recurring number. This can be shown by a number (in this case 6) with a dot above it.
(18 + 46)/6 = 10.666... or 10.67