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lisabon 2012 [21]
3 years ago
11

Solve the equation −3=8x−4y−3=8x−4y for y

Mathematics
1 answer:
AlekseyPX3 years ago
6 0
-3 = 8x - 4y
-3 - 8x = -4y
3/4 + 2x = y.....y = 2x + 3/4 <==


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Explain why 0.04/3.6 has the same answer as 4/360
lisov135 [29]
Because when you divide you get the same answer or something to do with percents
7 0
3 years ago
Which table shows a proportional relationship between x and y? please help and answer quick plz
gavmur [86]
The answer is c. 

(a)

x * 2 = y
2 * 2 = 4 
3 * 2 = 6
4 * 2 = 8 not 9

(b)

unknown formula

(c)

x * 3 = y
4 * 3 = 12 
5 * 3 = 15
6 * 3 = 18

(d)

x * 4
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3 0
3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
Which is the simplified rational expression for r2-4r+5/r-4
Sliva [168]

Step-by-step explanation:

\frac{ {r}^{2}  - 4r + 5}{r - 4}  -  \frac{ {r}^{2}  + 2r - 8}{r - 4}  \\  =  \frac{ ({r}^{2} - 4r + 5) - ( {r}^{2}  + 2r - 8) }{r + 4}  \\  =   \frac{ {r}^{2} -  {r}^{2}  - 4r - 2r + 5 - 8 }{r - 4}  \\  =   \frac{ - 6r - 3}{r - 4}

8 0
2 years ago
What are the solutions to x2 – 10x = 39?
oee [108]

Answer: x=−3 or x=13

Step-by-step explanation:

Step 1: Subtract 39 from both sides.

x2−10x−39=39−39

x2−10x−39=0

Step 2: Factor left side of equation.

(x+3)(x−13)=0

Step 3: Set factors equal to 0.

x+3=0 or x−13=0

x=−3 or x=13

7 0
2 years ago
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