Answer:
43091.3 or 43181.81(81 repeated)
Step-by-step explanation:
There are two answers because it depends on the method you use. You can get the second answer by plugging 95 into the equation gram*0.0022=pound or gram=(pound/0.0022). When you insert the 95, you get 43181.81(81 repeated).You can find the first answer by just looking it up on the conversion chart on google.
The explicit formula for given sequence is: 
Step-by-step explanation:
Given sequence is:
-1,4,-16,64.....
We can see that there is no same difference between consecutive terms so we will find common ratio to see if it is a geometric sequence.
Here
The explicit formula for geometric sequence is:
Putting the values of r and a1
Hence
The explicit formula for given sequence is:
Keywords: Geometric sequence, common ratio
Learn more about geometric sequence at:
#learnwithBrainly
Hi there!
The answer would be A. m = 45h
Hope this helps
Answer:
4096
Step-by-step explanation:
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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