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Murrr4er [49]
3 years ago
8

One cylinder has a volume that is 8 Centimeters cubed less than StartFraction 7 over 8 EndFraction of the volume of a second cyl

inder. If the first cylinder’s volume is 216 Centimeters cubed, what is the correct equation and value of x, the volume of the second cylinder?
StartFraction 7 over 8 EndFraction x + 8 = 216; x = 182 centimeters cubed
StartFraction 7 over 8 EndFraction x minus 8 = 216; x = 196 centimeters cubed
StartFraction 7 over 8 EndFraction x + 8 = 216; x = 238 centimeters cubed
StartFraction 7 over 8 EndFraction x minus 8 = 216; x = 256 centimeters cubed
Mathematics
2 answers:
nataly862011 [7]3 years ago
7 0

Answer:

D. StartFraction 7 over 8 EndFraction x minus 8 = 216; x = 256 centimeters cubed

vlada-n [284]3 years ago
3 0

Answer:

  • D. StartFraction 7 over 8 EndFraction x minus 8 = 216; x = 256 centimeters cubed

Step-by-step explanation:

<u>Equation for the volume and solution:</u>

  • 7/8x - 8 = 216
  • 7/8x = 216 + 8
  • 7/8x = 224
  • x = 224*8/7
  • x = 256 cm³

Correct option is D.

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