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avanturin [10]
3 years ago
5

There is a circle with a diameter of 3. Round to nearest tenth!

Mathematics
1 answer:
Yuliya22 [10]3 years ago
4 0

Answer:

Step-by-step explanation:

What is the Radius?

1.5

this is just 1/2. 1/2 of 3 is 1.5 (also you can look up how do you find the radius of a circle with the diameter to be sure, a calculator will come up and you can put in the diameter)

What is the Circumference?

9.4

You can figure out the Circumference by multiplying pi by the diameter. (also you can look up how do you find the circumference of a circle with the diameter to be sure, a calculator will come up and you can put in the diameter)

What is the Area?

7.1

how you find the area with just the diameter is 1 /4πd^2 (also you can look up how do you find the area of a circle with the diameter to be sure, a calculator will come up and you can put in the diameter)

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Mario claims that a rhombus is sometimes a square, but a square is always a rhombus. Is he correct? Explain your answer
Yuki888 [10]
That is correct.This is because a square has all the elements a rhombus has.A rhombus has 4 equal sides,just like a square does.And,a rhombus can't always be a square becase a square also contains 4 equal angles,while a rhombus doesn't.
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3 years ago
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What is the quotient of 29,596÷28?
cupoosta [38]

Answer:

√ 96

log

( 7 )

6 ! /3 !

Step-by-step explanation:

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3 years ago
Which expression has a value that is equivalent to 5n + 13 when n=−5 ?
Valentin [98]
5n + 13.....n = -5
5(-5) + 13 =
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-12

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5 0
3 years ago
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5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim
Ne4ueva [31]

Answer:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

S_p=2.940

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

df=60+72-2=130

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

n_1 =60 represent the sample size for people who used a self service

n_2 =72 represent the sample size for people who used a cashier

\bar X_1 =5.2 represent the sample mean for people who used a self service

\bar X_2 =6.1 represent the sample mean people who used a cashier

s_1=3.1 represent the sample standard deviation for people who used a self service

s_2=2.8 represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

And t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

System of hypothesis

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1 < \mu_2

This system is equivalent to:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2 < 0

We can find the pooled variance:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

And the deviation would be just the square root of the variance:

S_p=2.940

The statistic is given by:

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

The degrees of freedom are given by:

df=60+72-2=130

And now we can calculate the p value with:

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0
3 years ago
HELLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
rodikova [14]

Answer:

16%

Step-by-step explanation:

Blue = 6

Green = 7

Purple = 5

Red = 4

Orange = 3

25 Students in total

Probability of Red = 4/25

Or 16/100

16%

8 0
2 years ago
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