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Sindrei [870]
3 years ago
9

M= -2​, b 7/2 Enter the equation of the line in​ slope-intercept form.

Mathematics
1 answer:
mart [117]3 years ago
3 0

slope intercept form:

y=mx+b

m=-2, b=7/2

answer:

y=-2x+7/2

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A distribution has the five-number summary shown below. What is the range of this distribution? 24, 36, 42, 57, 65
inn [45]
Hello!

To find the range of the distribution, we must order the data from least to greatest (it has already been done) and then subtract the smallest value from the largest value in the set.

In this set, the smallest value is 24, and the largest value is 65. Subtract:

65 - 24 = 41

A N S W E R:

The range of the distribution below is A. 41.
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According to a certain central bank from 2000 to 2016 the average price of a new home in a certain region increased by ​%87 to ​
ch4aika [34]
X*1.87= 572
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3 years ago
Plz Solve Will Mark Brainliest and No Stealing Points Or Will Report<br> Part 2
jonny [76]

Answer:

Before we graph y = -\frac{1}{2}x, we know that the slope, mx, could be read as \frac{rise}{run}. To graph the the equation of the line, we begin at the point (0,0). From that point, because our rise is negative (-1), instead of moving upwards or vertically, we will move downards. Therefore, from point 0, we will vertically move downwards one time. Now, our point is on point -1 on the y-axis. Now, we have 2 as our run. From point -1, we move to the right two times. We land on point (2,-1). Because we need various points to graph this equation, we must continue on. In the end, the graph will look like the first graph given.

For the equation y = 2, the line will be plainly horizontal. Why? Because x has no value in the equation. The variable x does not exist in this linear equation. Therefore, it will look like the second graph below. We graph this by plotting the point, (0,2), on the y-axis.

7 0
3 years ago
1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera
Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}

SP \approx 8.246

PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}

PA \approx  8.246

AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}

AZ \approx 8.246

ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}

ZS \approx 8.246

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

m_{SA} = \frac{6-(-4)}{6-(-4)}

m_{SA} = 1

m_{PZ} = \frac{4-(-2)}{-2-4}

m_{PZ} = -1

Since m_{SA}\cdot m_{PZ} = -1, diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)

M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)

M_{SA} = (-2,-2)+(3,3)

M_{SA} = (1,1)

M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)

M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)

M_{PZ} = (2,-1)+(-1,2)

M_{PZ} = (1,1)

Then, the diagonals SA and PZ bisect each other.

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3 years ago
In the figure below, F is between E and G, and G is between F and H. IF EH=9, FH = 7, and EG=6, find FG.
shutvik [7]

Answer:

EH = 9

FH = 7

EG = 6

EF = EH - FH

EF = 9 -7

EF = 2

FG = EG -EF

FG = 6 -2

FG = 4

Step-by-step explanation:

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4 years ago
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